3 + h = 3 + 100.25 = 103.25
(2h-3)(h+1) = 0 h = 3/2 or h = -1
15
12 - h = -h + 3 Collect like terms giving 12 - 3 = -h + h ie 9 = 0 Something wrong somewhere!
-1
soot
dicarbon trihydrogen
The empirical mass is C2H3 2 x 12 = 24 3 x 1 = 3 24 + 3 = 27 So divide 27 into 166.01 Hence 162.27 / 27 = 6.01 ~ 6 So multiply each atom in the empirical formula by '6' Hence Empirical C2H3 Molecular C12H18
C4H6. C2H3 gives a molecular mass of 27, 54/27 gives 2. Therefore the molecular formula is twice the empirical formula.
Emperical formula FOR C8H12 is C2H3
H 3 H 3 that is who boo.
3 + h = 3 + 100.25 = 103.25
You can easily derive it from formula for the derivative of a power, if you remember that the cubic root of x is equal to x1/3. This question asks for the proof of the derivative, not the derivative itself. Using the definition of derivative, lim f(x) as h approaches 0 where f(x) = (f(a+h)-f(a))/h, we get the following: [(a+h)1/3 - a1/3]/h Complete the cube with (a2 + ab + b2) Multiply by [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] / [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] This completes the cube in the numerator, resulting in the following: (a + h - a) / (h × [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3]) h / (h × [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3]) h cancels 1 / [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] Now that we have a function that is continuous for all h, we can evaluate the limit by plugging in 0 for h. This gives 1/[a2/3 + a1/3 × a1/3 + a2/3] Simplify a1/3 × a1/3 1/[a2/3 + a2/3 + a2/3] (1/3)a2/3 or (1/3)a-2/3 This agrees with the Power Rule.
(2h-3)(h+1) = 0 h = 3/2 or h = -1
The empirical formula of organic compounds is the lowest whole number ratio of atoms contained in the substance, as defined in chemistry. The empirical formula gives the minimal ratio of the number of various atoms that exist. It's an empirical formula, if the formula is shortened, but not the exact number of atoms in the molecule, C4H6 is the chemical formula for butane. For every mole of carbon, there are two moles of hydrogen. The carbon-to-hydrogen ratio equals 2:3. C2H3 is the empirical formula for butane (C4H6). Hence, the correct answer is C2H3.
15
12 - h = -h + 3 Collect like terms giving 12 - 3 = -h + h ie 9 = 0 Something wrong somewhere!