no red uses more energy
Blue light is diffracted more than red. The way I remember is by thinking about the waves being closer together in the blue light and knowing that each wave interacts with the whatever is causing the diffraction (grating or object). More waves in a given area means more interaction which means more diffraction.
Yes it does.
Brighter light has more energy.
It is easier to see when it is yellow. It produces more heat energy and less light energy when it is blue. The yellow flame produces more light energy than heat energy. That makes it more visible
Red does as it absorbs photons at blue end of the spectrum( the higher energy) and reflects light at the red end of the spectrum (a lower energy). While the blue light absorbs energy at the red end of the spectrum and reflects blue light
The blue part of the spectrum has more energy than the red part.
The red light is lower energy than the blue light.
Blue light has more energy.Using the formula:photon energy (E) = Planck constant (h) * frequency (ƒ) Blue has a higher frequency than red. Since h is constant, E increases as ƒ increases.Using the formula:photon energy (E) = Planck constant (h) * speed of light (c) / wavelength (λ)Blue has a shorter wavelength than red. Since h and care considered constant, E increases as λ decreases.
Red light has lower energy photons than blue light. Ultra-violet is even more energetic.
When a star is blue it means it is putting out light mostly in the ultraviolet spectrum which is of a higher energy than infared light, or light in the visible spectrum. This means the star has more energy and heat.
Blue and yellow colors make green color. Blue has got more energy than yellow color. So green color will have more energy than yellow color. Hence proved.
Red light has less energy per photon than blue light, so to get the same energy we would need more red photons.