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In NaBH4 the boron atom is surrounded by four hydrogen atoms when it reacts with acetic acid three hydrogens are replaced by acetate group but 4th does not because boron is a smaller atom and can not attached to four acetate groups in a tetrahedral structure boron is attached to three acetate and one hydrogen atom having a negative charge which is balanced by ionic bod with Sodium atom.

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Q: Why does sodium boro hydride does not lose fourth hydrogen when react with acetic acid?
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