The gun weighs MUCH more than the bullet.
The bullet fired from a gun has greater horizontal acceleration. For vertical acceleration, they are both the same.
The acceleration of the bullet is greater than the acceleration of the rifle because the bullet has a much smaller mass. Newton's second law, F=ma, states that the acceleration is inversely proportional to mass given the same force, so the smaller mass of the bullet results in a greater acceleration for the same force applied.
No, the force of the gun results from the explosion of the gunpowder, propelling the bullet forward. The force of the bullet is the result of the acceleration it receives from the gun's explosion, which propels it in the opposite direction.
Newton said "For every action, there is an equal and opposite reaction." The action is pushing the bullet in one direction. Reaction is the gun being pushed in the other. The energy is speed times mass. The gun masses much more than the bullet, and so will move proportionately slower than the bullet. Which is a very good thing- or the recoil of the gun would kill the shooter.
Both objects accelerate, however due to Newton's 2nd law the acceleration of the rifle is less due to it's higher mass. Newton's second law F = ma In your question the force (F) would be the same on both objects, but the mass (m) would be different and give a different answer for acceleration (a). This difference can be seen by looking at the effect of being on opposite sides of the rifle (ie kickback vs bullet hole)
A bullet does not accelerate after it leaves the barrel of a gun. It will decelerate. You could say it accelerates, but the acceleration would be negative. The bullet is accelerated by expanding gas as it moves down the barrel, and after it leaves the muzzle, there is no more acceleration imparted from expanding gas. We also find that air friction (drag) is acting to slow it down. Think this one through and it becomes obvious.
No- or minimal at best. Acceleration of the bullet comes from gas expanding inside the barrel, pushing the bullet. Once it leaves the barrel, (or within a VERY short distance) gas is no longer pushing, and acceleration stops, and bullet begins to slow from air resistance.
There is no single answer to this question. It will depend on the cartridge, and the characteristics of the powder and bullet being fired. For instance, the 40 gr 22 Long Rifle cartridge accelerates from the moment of firing, until it travels about 12 inches. The gas produced by firing reaches it's max expansion, and the bullet now begins to SLOW to some degree from friction with the barrel. Acceleration is NOT uniform with any firearm cartridge- if graphed it would be a curve with a very sharp spike.
Depends on the gun. A .22 will have very different pressures from a 30-06.
A cartridge will ignite if the primer is struck, regardless of whether it is in a gun at the time.
Newton's 3rd law: for every action there is an equal and opposite direction reaction. The force of the bullet under acceleration reacts against the gun and therefore the gun jerks against the person holding it.
Yes, a gun is considered a third-class lever because the effort (trigger finger) is placed between the load (bullet) and the fulcrum (pivot point). When the trigger is pulled, the force is exerted close to the fulcrum, allowing for efficient acceleration of the bullet.