0
Why does the current in an electric circuit decrease when more bulbs are added?
Wiki User
∙ 14y ago
If you add one extra bulb and the voltage remains constant, then you have doubled the current drained from the regulator.
12 Volt and One 12 Watt light bulb drains 1 Ampere Current.
12 Volt and Two 12 Watt light bulbs drains 2 Ampere Current.
However:
If having a 24 volt power source and you add two 12 Volt 12 Watt in serial, then you still only drain 1 Ampere Current.
NOTE:
Wattage and Voltage of bulbs may be different even if the sockets are the same.
Lower voltage on the bulb will increase the current drain, if voltage is a lot lower it might cause the circuit delivering voltage to burn out or blow a fuse. It can also quickly burn the bulb, sometimes in a fraction of a second.
It will however do little damage to add a bulb with higher voltage than the circuit is designed for. You will then only observe that you do not get the light you might hope for.
Total Current/Ampere= Combined Wattage divided by Voltage
Total Wattage = Combined Current or Ampere multiplied by Voltage.
In simpler words:
If you double the bulbs, twice the current is drained from the battery
Wiki User
∙ 13y ago
Wiki User
∙ 14y agoAdding bulb means adding resistance. With increase in resistance, current decrease.
Add your answer:
Earn +20 pts
If you have a DC passing through a circuit will the current decrease when you add a DC motor and if so by how much?
In the circuit where the DC motor is added, it was not specified whether the motor was added in series or in parallel to circuit elements. If it was added in series, it will increase circuit resistance and it will cause circuit current to go down. In parallel, the motor will reduce total circuit resistance, and circuit current will increase.
What happens to the current flowing in the ring main as more bulbs are turned on at night?
As more light bulbs are added in a series circuit, the effective resistance of the circuit increases. That causes the current leaving the source to decrease.
What is added to a circuit to make the current smaller?
The reduction of voltage or the increase of resistance will reduce the current in a circuit.
What changes occur in the total resistance of a circuit as additional resistances are added in parallel?
The total resistance of the circuit increases. hence the new resistance after adding the resistance will be new resistance = old resistance + added Resistance There is a small mistake in the question. The second word is 'changes' not 'charges'
What happens to the total resistance of a series circuit when another resistor is added?
Simply put, the purpose of a resistor is to 'resist' the flow of current. Ohm's Law tells us that for a given voltage, the larger the resistance, or value of that resistor, the lower the current that will flow. Ohm's Law states that I (current) = E (voltage) / R (resistance) - where current is measured in amps, voltage is measured in volts and resistance is measured in ohms.
Why does the electric current decrease when an additional bulb is added to the circuit in series?
becase the electricity is taken by both bulbs and it is divided
What would be different about the circuit if a resistor were added in series with the light bulbs?
The total current in the circuit will decrease.
If you have a DC passing through a circuit will the current decrease when you add a DC motor and if so by how much?
In the circuit where the DC motor is added, it was not specified whether the motor was added in series or in parallel to circuit elements. If it was added in series, it will increase circuit resistance and it will cause circuit current to go down. In parallel, the motor will reduce total circuit resistance, and circuit current will increase.
Why external resistances are added to armature circuit in a dc motor?
extra resistance is added in order to decrease starting current and improve starting torque
When an ammeter is connected to measure current circuit current will decrease sightly because R total decreases after the meter is inserted?
Current will be decreased because of the resistance of the ammeter added to the circuit's resistance. In other words total resistance increases.
What happens when one or more light bulbs are added to the circuit?
A: If put in series current will decrease if put in parallel current will increase assuming the input voltage remains the same
What happens to the current flowing in the ring main as more bulbs are turned on at night?
As more light bulbs are added in a series circuit, the effective resistance of the circuit increases. That causes the current leaving the source to decrease.
In a series circuit each device that is added to the circuit decreases the what?
Depends on the device. If it is a resistor and you have a fixed voltage then the circuit will obey Ohms law. Voltage = Current x Resistance. So if R increases by adding more resistors in series and the voltage is constant, the current will decrease.
In a series circuit as more bulbs are added the bulbs get dimmer the electric current through each bulb?
By adding more light bulbs
What is added to a circuit to make the current smaller?
The reduction of voltage or the increase of resistance will reduce the current in a circuit.
What changes occur in the total resistance of a circuit as additional resistances are added in parallel?
The total resistance of the circuit increases. hence the new resistance after adding the resistance will be new resistance = old resistance + added Resistance There is a small mistake in the question. The second word is 'changes' not 'charges'
Why is circuit current reduced when a capacitors added to the circuit?
In the case of an a.c. circuit, capacitors oppose current because of their capactive reactance, expressed in ohms. Capacitive reactance is inversely-proportional to the capacitance of the capactor and to the frequency of the supply. So, adding a capacitor is series with an existing load will reduce the load current. On the other hand, adding a capacitor in parallel with an existing load will decrease the load current.
