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The method you would use is to take a graduated cylinder, face the markings towards you, fill the cylinder with a liquid that won't react with said object (usually water is fine) to an appropriate measure (around half way depending on the size of the object), record the volume before placing the object in the fluid, place the object in the fluid and record the volume after, subtract the initial from the total (liquid +object's displacement) and you will have the objects volume. However you must be aware that certain objects will float or at least have some amount of buoyancy making determining it's volume harder to ascertain (if at all possible) with this method.
"displacement volume"
Measure the mass and volume of the object. Divide the mass by the volume.
Use volume displacement method.
If the shape of the object is regular (a cube or a sphere) then the volume can be calculated from the measurement of the object's key dimension(s). And the object's mass can be determined in a mass balance. Give the mass and volume the density is calculated by dividing the mass by the volume. Where the object's shape is irregular, the volume may be determined by measuring the volume of a liquid displaced by submerging the object completely in that liquid.
There are 12 inches.
It depends on what the second method is!
The Proper way to find the density of an object is by dividing the objects Mass by its Volume. (Density broke my Heart) Mass/Volume = Density
The method for determining the volume of a solid depends on its shape. The volume of a solid object with a regular geometric shape (rectangular box, cube, cylinder, sphere) can be determined using the volume formula for the shape. Because many objects are not regularly shaped their volume cannot be determined using a volume formula. The volume of these objects can be found by water displacement. A volume of water sufficient to cover the object is placed in a graduated cylinder and the volume read. The object is added to the cylinder and the volume read again. The difference between the two volumes is the volume of the object.
Simply because the volume of water displaced is not equal to the actual volume of the object. If an object is lighter than water, you have to find another method of determining its volume. ------------------------------------ alternatively you could use a very thin pin to push the object under the water. However, the volume of the submerged portion of the pin would need to be suvtracted from the volume of the object measured.
It depends on what the second method is!
method usede to figure the volume of an irregular shaped object
Because only regular-shaped objects have a consistent length, width, height, and shape. When dealing with an object composed of differing shapes, your must calculate each portion separately and then add them. For instance, if you have a swimming pool of two depths and want to determine cubic feet, you would have to calculate the volume for each section and then add them.
Archimedes
Displacement method.... Is the method to find volume of an irregular object
The method you would use is to take a graduated cylinder, face the markings towards you, fill the cylinder with a liquid that won't react with said object (usually water is fine) to an appropriate measure (around half way depending on the size of the object), record the volume before placing the object in the fluid, place the object in the fluid and record the volume after, subtract the initial from the total (liquid +object's displacement) and you will have the objects volume. However you must be aware that certain objects will float or at least have some amount of buoyancy making determining it's volume harder to ascertain (if at all possible) with this method.
"displacement volume"