Because carbonic acid is diprotic.
The Kb of Na2CO3 is equal to 2.1 x 10^-4. Carbonate ion is the ion that results from the dissociation of Na2CO3.
Ca(OH)2 + Na2CO3 = CaCO3 + 2 NaOH
The molecular weight of Na2CO3 is: (2 X 23) + 12 + (3 X 16) = 106
Molecularity is the sum of stoicheometric coefficients of the reactants in a chemical reaction.2 AgNO3 + Na2CO3 = Ag2CO3 + NaNO3The molecularity is: 2 (from AgNO3) + 1 (from Na2CO3) = 3
Na2CO3 (aq) + CaCl2 (aq) -----> 2 NaCl(aq) + CaCO3(s) This is a double displacement reaction.
The Kb of Na2CO3 is equal to 2.1 x 10^-4. Carbonate ion is the ion that results from the dissociation of Na2CO3.
sodium: Na + carbonate: CO3 2- therefore... Na2CO3 the "2" and "3" are subscripts
Ca(OH)2 + Na2CO3 = CaCO3 + 2 NaOH
2, a sack in the end zone is considered a safety which is 2 points
Na2CO3 + 2 NH4OH = (NH4)2CO3 + 2 NaOH
The molecular weight of Na2CO3 is: (2 X 23) + 12 + (3 X 16) = 106
The end points are 7 and 2.
A line segment is between two end points
The answer is TWO (2)Na2CO3 + CaCl2 --> 2 NaCl + CaCO3
The shape that has 2 end points is known as a line segment. A line segment is a line that can go on forever, but it has a start point and an end point, no matter where it stops.
The formula mass of sodium carbonate, Na2CO3 is 2(23.0) + 12.0 + 3(16.0) = 106.0Amount of Na2CO3 = mass of sample/molar mass = 0.75/106.0 = 0.00708mol There are 0.00708 moles of Na2CO3 in a 0.75g pure sample.
Only chemical formulas, not if they are reacting. Na2CO3 and CaCl2