The molecular weight of Na2CO3 is: (2 X 23) + 12 + (3 X 16) = 106
the answer to your question is 0.0004 g/mol.
This equation is: 2CH3COOH + Na2CO3 --> 2NaCH3COO + CO2 + H2O .
NaHSO4 is the molecular formula for sodium bisulfate, and Na2CO3 is sodium carbonate. The reaction of:2NaHSO4 + Na2CO3 yields 2Na2SO4 + CO2 + H2O. The gas product is carbon dioxide (gas) of formula CO2.
The molecular weight of vanillideneacetone is 192.214g/mol.
The balanced chemical equation for this reaction is 2 HCl + Na2CO3 -> 2 NaCl + H2O + CO2. From the equation, 1 mole of Na2CO3 reacts with 2 moles of HCl. Calculate the number of moles of Na2CO3 in 4000g, then use the mole ratio to find the moles of HCl needed. Finally, convert moles of HCl to grams.
the answer to your question is 0.0004 g/mol.
When heating sodium carbonate decahydrate (Na2CO3·10H2O), it loses water molecules as it converts to anhydrous sodium carbonate (Na2CO3). The molecular weight of Na2CO3·10H2O is approximately 286 g/mol, while that of anhydrous Na2CO3 is about 106 g/mol. The weight lost due to the water is around 180 g/mol (from 10 moles of water), leading to a percent loss in weight of approximately 62.9%.
mass of Na2CO3 with 10H2O of crystallisation is 286g
Na2CO3 + H2SO4 --> Na2SO4 + H2O + CO2
This equation is: 2CH3COOH + Na2CO3 --> 2NaCH3COO + CO2 + H2O .
NaHSO4 is the molecular formula for sodium bisulfate, and Na2CO3 is sodium carbonate. The reaction of:2NaHSO4 + Na2CO3 yields 2Na2SO4 + CO2 + H2O. The gas product is carbon dioxide (gas) of formula CO2.
It has a molecular weight of 21,600 Daltons
molecular structur C9H8K2O4molecular weight: 258.35
To determine the equivalent weight from the molecular weight, you need to divide the molecular weight by the valence (or charge) of the compound. For example, for a compound with a molecular weight of 100 g/mol and a valence of 2, the equivalent weight would be 50 g/equiv.
The molecular weight of vanillideneacetone is 192.214g/mol.
These two compounds doesn't react.
The balanced chemical equation for this reaction is 2 HCl + Na2CO3 -> 2 NaCl + H2O + CO2. From the equation, 1 mole of Na2CO3 reacts with 2 moles of HCl. Calculate the number of moles of Na2CO3 in 4000g, then use the mole ratio to find the moles of HCl needed. Finally, convert moles of HCl to grams.