because you are not in the sun and the uv rays arent hitting you anymore(if you're inside)
No ive had it for 14 years and i tan better than my whole family
Be an hero
From what Ive herd yes u can just use an umbrella a lot or don't play 4 a while
Purposely tanning is never a good idea--it increases the risk of skin cancer, prematurely ages skin, and can cause painful burns. Sunblock should be worn whenever your skin is exposed to the sun for long periods of time. If you insist on tanning, it's probably better to wait until 6 weeks, when your hormone levels have all returned to normal. This decreases the risk of melasma, dark patchy staining of the face
Your best bet is to buy tanning color lotion. I think neuatragena has one. And if you can't get that, lay in your backyard for an hour. BUT still put on sun tan lotion because burnt is NOT tan.
The only way to find out which products will work best for you and have the most favorable result is to try them out for yourself. Some of the spray tan products with the best reviews online include Mystic Tan UV-Free Spray On Tan and Jergens Natural Tan Revitalizing Moisturizer.
I would look at your tanning salon products and see what they offer. I would also get a spray tan professionally.
The best way to do a home spray tan is to go to Wal-Mart and look at the various home spray tans that are available. The best one is Neutrogena, because it is less streaky and easier to put on then some of the other varieties.
tan(9) + tan(81) - tan(27) - tan(63) = 4
Tan Tan
Well every sunny day i lay out for aproximately 5 hours... but if I'm not tan enough i rub fake tanner and avocado on. it works like charm!!
This may not be the most efficient method but ... Let the three angle be A, B and C. Then note that A + B + C = 20+32+38 = 90 so that C = 90-A+B. Therefore, sin(C) = sin[(90-(A+B) = cos(A+B) and cos(C) = cos[(90-(A+B) = sin(A+B). So that tan(C) = sin(C)/cos(C) = cos(A+B) / sin(A+B) = cot(A+B) Now, tan(A+B) = [tan(A)+tan(B)] / [1- tan(A)*tan(B)] so cot(A+B) = [1- tan(A)*tan(B)] / [tan(A)+tan(B)] The given expressin is tan(A)*tan(B) + tan(B)*tan(C) + tan(C)*tan(A) = tan(A)*tan(B) + [tan(B) + tan(A)]*cot(A+B) substituting for cot(A+B) gives = tan(A)*tan(B) + [tan(B) + tan(A)]*[1- tan(A)*tan(B)]/[tan(A)+tan(B)] cancelling [tan(B) + tan(A)] and [tan(A) + tan(B)], which are equal, in the second expression. = tan(A)*tan(B) + [1- tan(A)*tan(B)] = 1