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Why doesn't the acid of the buffer react with the added conjugate base although it's a weak acid and according to Le Chatelier when adding the conjugate base it should shift the equilibrum and reform?
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Why does a solution of a conjugate acid base pair behave as a buffered solution?
The resist pH change in the following way: If you add a strong acid to the buffer solution, the conjugate base gets protonated, but the pH is not significantly changed. If you add a strong base to the buffer, the conjugate acid gets deprotonated, and again the pH is not changed very much. If you only had one component (let's say just the conjugate base), then it would not be able to resist change in pH if you added a strong base to the solution (although it would still counteract the affect of added acid).
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What does Le Chatelier's principle state?
A reaction at equilibrium will respond to balance a change - apex (Explanation): The answer is NOT "a new equilibrium ratio will form", because although this is true, it will not necessarily always happen and is not what le chatelier's principle is about. His principle focuses on the reaction changing to cancel out or balance the change in equilibrium. Therefore, this is the correct answer.
What does Le chateliers principle state (apex)?
A reaction at equilibrium will respond to balance a change - apex (Explanation): The answer is NOT "a new equilibrium ratio will form", because although this is true, it will not necessarily always happen and is not what le chatelier's principle is about. His principle focuses on the reaction changing to cancel out or balance the change in equilibrium. Therefore, this is the correct answer.
Why chcl3 is more acidic than chf3?
So the idea behind determining which compound is more acidic is linked to the stability of the conjugate bases. The more stable the conjugate base, the easier it is for the compound to lose a proton, the more acidic the compound. Comparing the two conjugate bases, CF3- and CCl3-. The negative charge on CF3- is stabilised by the induction effect of the electronegative fluorine while the negative charge on CCl3- is stabilised by both induction effects of chlorine and by delocalisation. This delocation can happen in CCl3- because the filled 2p orbitals of C can overlap with the empty 3d orbitals of Cl which lowers the energy. Some people call this backbonding. However F does not have empty d orbitals and this overlap cannot occur. Therefore, although the induction effect of F is stronger, the combination of induction and back bonding effect better stabilises the conjugate base in CHCl3, making it a stronger acid.
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