This is kind of sticky to explain. A flow of electrons is exactly like distance in geometry - the shortest distance between two points is a straight line. Distance in wiring is increased resistance. In a circuit board 8 inches square, the fact that the wire has to make a bend has negligible effect on the resistance. In a spring reverb unit, the current is going through a tightly wound coil that is eight inches long - but actually represents about 30 inches of wire. That slows the current down to an extent because of the added resistance.
Yes, bends in a wire can increase its electrical resistance due to the deformation of the metal lattice structure, which interrupts the flow of electrons. This increased resistance can lead to energy losses in the form of heat.
Bends in a wire do not affect its resistance because the cross-sectional area and length of the wire remain the same regardless of the bends. Resistance is determined by these two factors, according to the formula R = ρ*(L/A), where ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area. As long as these parameters remain constant, the resistance of the wire will stay the same.
Unless the wire is broken, a bent wire should still be able to conduct electricity as well as a straight one.
Bending a wire can change its resistance due to changes in its length and cross-sectional area. However, resistivity, which is an intrinsic property of the material, remains constant regardless of bending.
Its elemental makeup. Its' diameter and its' length.
Increasing the wire gauge from AWG 22 to AWG 26 will increase the wire's resistance because a higher gauge corresponds to a thinner wire. Thinner wires have higher resistance due to increased electrical resistance per unit length. Therefore, a wire with AWG 26 will have higher resistance compared to a wire with AWG 22.
If a resistive wire is elongated, its resistance will increase. This is because the longer length of wire will result in more collisions between electrons and the wire's atoms, leading to higher resistance. The resistance of a wire is directly proportional to its length.
it will not effect it because it only depends upon property of medium
As temperature increases, the resistance of a wire also increases. This is because as the temperature rises, the atoms in the wire vibrate more vigorously, causing more collisions with electrons and impeding the flow of current. This relationship between temperature and resistance is known as the temperature coefficient of resistance.
Assuming the wire follows Ohm's Law, the resistance of a wire is directly proportional to its length therefore doubling the length will double the resistance of the wire. However when the length of the wire is doubled, its cross-sectional area is halved. ( I'm assuming the volume of the wire remains constant and of course that the wire is a cylinder.) As resistance is inversely proportional to the cross-sectional area, halving the area leads to doubling the resistance. The combined effect of doubling the length and halving the cross-sectional area is that the original resistance of the wire has been quadrupled.
Changing the thickness of the wire will affect its resistance. Thicker wire has lower resistance, allowing more current to flow through it with less energy loss as heat. Thinner wire has higher resistance, restricting the flow of current and causing more energy to be lost as heat.
less current will flow as resistance is inversely proportional to area