answersLogoWhite

0


Want this question answered?

Be notified when an answer is posted

Add your answer:

Earn +20 pts
Q: Why first order reaction never completes?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the reaction order of the decomposition of nitrogen pentoxide?

it is first order reaction...


How do you prove graphically that a reaction is first order?

If a reaction is first order, a graph of reaction rate against reagent concentration will be a straight line.


What is the unit of first order reaction?

A zero-order reaction is a reaction that proceeds at a rate that is independent of reactant concentration. Typically with increasing or decreasing reactants


How is order of reaction determined graphically?

in our syllabus there is only the first and the zero order reaction in which if the graph is plotted between the concentration and time then it is a zero order reaction while if the graph is between the log of concentration and time then the reaction is of the first order.hope this will help u.


75 of a first order reaction was found to complete in 32 minutes When will 50 of the same reaction complete?

If 75 of a first order reaction was complete in 32 minutes then 50 of the same reaction will complete in 21 minutes 18 seconds.


What is first order cycle reversible reaction?

A 4carbon compound


X is second order and Y is first order X plus Y-- XY Does the reaction occur in a single step in which X and Y collide?

Yes, the reaction occurs in the step where X and Y collide. The first step is part of an elementary reaction and in an elementary reaction, the order is nothing but the coefficient in front of the reactant.


How is rate of a chemical reaction usually expressed?

Rates of reaction can be expressed depending upon their order.For example say you have a reaction between two chemicals and the initial rate for that reaction is known :-when:-The concentration of one of the reactants is doubled and the other reactants concentration remains the same and the overall rate of reaction does not change - reaction is zero orderwith respect to chemical which was doubled.The concentration of one of the reactants is doubled and other reactants concentration remains the same and the overall rate of reaction doubles - reaction is first order with respect to chemical which was doubled.The concentration of one of the reactants is doubled and other reactants concentration remains the same and the overall rate of reaction quadruples - reaction is second order with respect to chemical which was doubled.Zero Orderrate = kFirst Orderrate = k [A] (reaction is 1st order with respect to [A] and 1st order overall)Second Orderrate = k [A][B] (reaction is first order with respect to [A] and first order with respect to[B], reaction is second order overall)rate = k [A]2 (reaction is second order with respect to [A] and second order overall)Orders are simply added together in order to determine the overall order of reaction :-rate = k [A][B][C] would be third order overall and first order with respect to each of the reactantsThere are other orders of reaction, for example 2 and 3 quarter orders and third order reactions, but these are a little more complex.


Why radioactivity is considered as a first order reaction?

Radioactivity is the disintegration of the substance by its own. This means disintegration depends only on one reactant concentration i.e.,on itself. So this is a first order reaction.


How do you identify whether the order of the reaction is zero order first order or second order?

Linear system of arbitrary complexty can be viewed as being composed of first and second order


What is meant by the order of a chemical reaction?

The reaction order is the law in which determines which elements will begin the process first. It is dependent upon the Kinetic energy of each element. The reaction order in chemistry is difficult to determine.


Which order of reaction does radioactive elements involve?

I believe it is a first order reaction. So the integrated rate law would be: ln[A]final = -kt + ln[A]inital