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Increasing flux, torque of the dc motor will be increased and speed of the dc motor will be decreased as speed of the dc motor is inversely proportional to that of the flux and the torque of the dc motor is directly proportional to the flux.
on adding load on a dc shunt motor, the amount of current and torque will increase. but terminal voltage will decrease
How do you calculate voltage drop for starting motor current
variable voltage control has some limitations as you decrease the voltage corresponding phase current will increase lead to increase of flux which lead to saturation of motor core and heating of motor to make flux constant and vary speed of motor v/f ratio need to be maintained constant
There are 746 watts in 1 HP. Watts = amps x volts. It depends on the voltage rating of the motor. Amps = 746/volts = ? need voltage.
Based on the simplest Electrical Equation V = I * R,(reads: voltage equals current multiplied by resistance)then, rearranged I = V / R .As resistance decreases, current flow proportionately increases
If you're talking about an electric motor, increasing the frequency will increase the speed of rotation of the motor, and decreasing the frequency will decrease the speed of rotation of the motor. The other way of controlling a motor is to control the current; increasing the current increases speed, decreasing current decreases speed.
A constant KVA load is an electrical load which has a constant apparent power consumption regardless of small changes in voltage. Constant KVA loads in industry are typically electric motor loads such as induction motors. The interesting thing about an induction motor and why it is called a constant KVA load is, for a constant level of torque output of the motor, if the terminal voltage decreases by say 5% the motor current will actually increase by about 5%. Note that this constant KVA effect will only occure withing an narrow range of voltage deviation. This is the opposite of a static (constant Z) load which if the voltage decreases the current decreases.
Increasing flux, torque of the dc motor will be increased and speed of the dc motor will be decreased as speed of the dc motor is inversely proportional to that of the flux and the torque of the dc motor is directly proportional to the flux.
on adding load on a dc shunt motor, the amount of current and torque will increase. but terminal voltage will decrease
How do you calculate voltage drop for starting motor current
variable voltage control has some limitations as you decrease the voltage corresponding phase current will increase lead to increase of flux which lead to saturation of motor core and heating of motor to make flux constant and vary speed of motor v/f ratio need to be maintained constant
as a motor armature speed increases,the net current in the motor windings decreases due to MAGNETIC DRAG. which is a common phenomenon in the ac machines.
To answer this question the voltage of the motor needs to be stated.
There are 746 watts in 1 HP. Watts = amps x volts. It depends on the voltage rating of the motor. Amps = 746/volts = ? need voltage.
Motors overheat due to excessive current, not necessarily voltage. Normal voltage can cause a motor to overheat if it is stuck (not spinning). The problem is not usually the voltage, but whatever is causing excessive current flow (usually because the motor is not spinning like it is supposed to).
What supplies a dc motor is not current, but voltage. Current is what flows in the circuit formed by the dc motor and for the charge. That current varies according to the resistance of the circuit.