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This question seems to be about the reactant side of a chemical equation. To calculate the mass of oxygen produced, you need to know the stoichiometry of the reaction. Without that information, it is not possible to determine why 160 grams of oxygen would be produced.

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1y ago

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When there are 3 grams of carbon and 8 grams of oxygen if all of the carbon and oxygen reacted how many grams of carbon dioxide are produced?

11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.


In a laboratory 178.8 grams of water is separated into hydrogen gas and oxygen gasthe hydrogen gas has a mass of 20.0 grams what is the mss of the oxygen gas produced?

an equation showing conservation of mass of reactants and products:2H2O --> 2H2 & O2what is the mass of the oxygen gas produced, from 178.8 g H2O , (using molar masses:178.8 g H2O @ (1mol O2)(@ 32.00 g/mol) / (2molH2O)(18.02g/mol) =your answer (4 sigfigs): 158.8 g O2178.8 g H2O ---> 20.0 H2 & 158.8 O2


What is the mass of 3moles of oxygen?

The molar mass of oxygen is approximately 16 grams/mol. Therefore, the mass of 3 moles of oxygen would be 3 moles * 16 grams/mole = 48 grams.


How many grams of water are produced from 67g of oxygen?

67.5 grams of H2O


What mass of water decomposes to make 4 grams of hydrogen gas and32 grams of oxygen gas how do you know?

In chemistry, the outcome of a reaction must have the same mass as the initial state. This means that if you have 32g of oxygen and 4g of hydrogen, you just have to add the numbers to discover the original mass (in this case, 36g).


What is the mass of 0.8 grams of oxygen?

The molar mass of oxygen is approximately 16 grams/mol. Therefore, the mass of 0.8 grams of oxygen is equivalent to 0.8/16 = 0.05 moles.


How many grams of oxygen are produced in the decomposition of 6.02g of potassium chlorate?

The decomposition of potassium chlorate produces oxygen gas and potassium chloride. The molar ratio of oxygen to potassium chlorate is 3:2. Therefore, to find the grams of oxygen produced, you would calculate (6.02g * 3 mol O2/2 mol KClO3) * molar mass of O2.


How much mass 6.02 x 1023 atoms of oxygen have?

Just about 16 grams as what you have written in you question is Avogadro's number, which is a mole of anything. Oxygen is 16 grams per mole.


What is the mass in grams of 1mole of oxygen?

The mass of 2.000 mol of oxygen atoms is 32.00 grams.


How do you calculate how many grams of water are produced from 22.1 grams of oxygen?

First find the percentage by mass of oxygen in water. The formula for water is H2O, showing that water contains two hydrogen atoms for every atom of oxygen. The gram atomic masses of hydrogen and oxygen are 1.00794 and 15.9994 respectively. Therefore, the percentage of oxygen in water is 100{15.9994/[15.9994 + 2(1.00794)]} or about 88.8 %, to the justified number of significant digits; the ratio of the maximum mass of water that can be made from a given mass of oxygen is 1/0.888 or about 1.126; and the answer to the question is this number multiplied by the stated mass of oxygen, or 24.9 grams, to the justified number of significant digits.


What would be the total mass of the products of a reaction in which 10 grams of water decomposes into the elements of hydrogen and oxygen?

The total mass of the products would be 10 grams, as mass is conserved in a chemical reaction. When water decomposes into its elements, hydrogen and oxygen, the total mass of the products will be the same as the mass of the reactant.


How many grams of water are produced when 300 grams of hydrogen react with an unlimited amount of oxygen?

The atomic mass of hydrogen is 1.008 and the molecular mass of water, with formula H2O, is 18.015. Therefore, the mass of hydrogen to that of water has the ratio of 2(1.008)/18.015 = about 0.1119, and the answer to the problem is 300/0.1119 = 2.68 X 103 grams, to the justified number of significant digits.