A break down of 2d1:
2 = the quantum energy level or electron shell denoted as 'n'
d = the sub-shell of the energy level (known as a degenerate level)
1 = the number of electrons occupying the sub-shell.
Through extensive research by scientists, no known element has a d sub-shell in the second (n=2) energy level. In fact, the d sub-shell does not appear until the fourth period (fourth row).
The first d sub-shell is known to be in the third energy level (therefore the first energy level with this sub-shell is 3d, but not 2d).
Transition metals are the elements known to fill the d sub-shells. The first transition metal in the Periodic Table is scandium (Sc) with the electron configuration of [Ar]4s23d1.
The reasons for the formation of sub-shell of d is beyond my knowledge and the scope of basic chemistry.
To find out, if a number is divisible by 7, take the last digit, double it, and subtract it from the rest of the number. If you get an answer divisible by 7 (including zero), then the original number is divisible by 7.If you don't know the new number's divisibility, you can apply the rule again.Eg: Take the number 343The units digit is 3.Doubling this 3,we get 6.Subtracting 3 from 34(that is the remaining 2 digits in the number), we get 34-6=28.As 28 is divisible by 7, The whole number, i.e., 343 is divisible by 7.Proof of Divisibilty Rule for 7Let 'D' ( > 10 ) be the dividend.Let D1 be the units' digitand D2 be the rest of the number of D.i.e. D = D1 + 10D2We have to prove(i) if D2 - 2D1 is divisible by 7,then D is also divisible by 7and (ii) if D is divisible by 7,then D2 - 2D1 is also divisible by 7.Proof of (i) :D2 - 2D1 is divisible by 7 ⇒ D2 - 2D1 = 7k where k is any natural number.Multiplying both sides by 10, we get10D2 - 20D1 = 70kAdding D1 to both sides, we get(10D2 + D1) - 20D1 = 70k + D1⇒ (10D2 + D1) = 70k + D1 + 20D1⇒ D = 70k + 21D1 = 7(10k + 3D1) = a multiple of 7.⇒ D is divisible by 7. (proved.)Proof of (ii) :D is divisible by 7 ⇒ D1 + 10D2 is divisible by 7 ⇒ D1 + 10D2 = 7k where k is any natural number.Subtracting 21D1 from both sides, we get10D2 - 20D1 = 7k - 21D1⇒ 10(D2 - 2D1) = 7(k - 3D1)⇒ 10(D2 - 2D1) is divisible by 7Since 10 is not divisible by 7,(D2 - 2D1) is divisible by 7. (proved.)
Yes there is. Buslink makes a 4 port PCMCIA USB 2.0 Host controller, fo about $28. You can find one at http://www.mypcgoodies.com/details.asp?item=HM09101%2D1
How is what possible? How is what possible?
possible, search it on google
How is what possible?
Anything is possible! I think it can be possible...
more possible, most possible
Whether or not it is possible, it DOES nothing.Whether or not it is possible, it DOES nothing.Whether or not it is possible, it DOES nothing.Whether or not it is possible, it DOES nothing.
possible
it's possible is translated in French as "c'est possible"
It is quite possible that there is no mode.It is quite possible that there is no mode.It is quite possible that there is no mode.It is quite possible that there is no mode.
There are infinitely many possible answers.One possible pair is -125.37 and 2,000,000There are infinitely many possible answers.One possible pair is -125.37 and 2,000,000There are infinitely many possible answers.One possible pair is -125.37 and 2,000,000There are infinitely many possible answers.One possible pair is -125.37 and 2,000,000