Why is 7^0 = 1
Algebraic proof.
Let 'n' be any value
Let 'n be raised to the power of 'a'
Hence n^a
Now if we divide n^a by n^a we have n^a/n^a and this cancels down to '1'
Or we can write n^(a)/n^(a) = n^(a-a) = n^(0) , hence it equals '1'
Remember when the lower /denominating index is a negative power ,when raised above the division line.
7 to the power of 0 = 1
7 to the power of 1= 7
Any negative number to the power of 0 is always -1
71 is greater.
Anything to the power of 0 has an answer of 1. So 7⁰ = 1, as well as any other number you can think of.
7^0 = 1.
Any value to the power of 'zero' is equal; to '1' So 7^0 = 1 Similarly 7,000,000^0 = 1 Similarly 0.000007^0 = 1
Anything (except zero) to the power of zero is 1. If written as 7a0, this is operated as 7 x (a0) = 7 x 1 = 7. If written as (7a)0, it is simply 1 by the first statement.
75 divided by 73 = 72 by subtracting the powers Likewise 71 divided by 71 = 70 and so 7/7 = 1 Any number raised to the power 0 is always equal to 1 But any number times 0 is always equal to 0
Any number raised to the power of 0 will be 1. 1^0=1 3^0=1 59877658175631839756297346078964145016734207660^0=1 1. Anything to the power of 0 is 1
0 to the power 0 is 1 because any number power zero is always equal to 1.Anything to the power of 0 equals 1.
maybe 1 power of 0 is 1 is The answer is one (1)
(a to the power of 1)/(a to the power of 1)=1 So, a to the power of (1-1)=1 Therefore, a to the power of 0=1
0000001=1=10^0 .0000001=10^-7