4Zn + 10HNO3 (very dilute) --> 4 Zn(NO3)2 + N2O + 5 H2O
Zn + 4 HNO3 (Conc) --> Zn(NO3)2 + 2 NO2 + 2H2O
Zn + 2HNO3(aq) -> Zn(NO3)2(aq) + H2(g)
Zn + 2HCl --> ZnCl2 + H2
The equation is: Zn + 2HNO3 -----> Zn(NO3)2 + H2
Acid base reaction will occur when zinc oxide is added to nitric acid water and zinc nitrate (salt) are formed the equation is: ZnO + 2 HNO3 = Zn(NO3)2 +H2O
Zn + 2HCl >> ZnCl2 + H2 13.05 grams Zn (1mol Zn/65.41g Zn)(1mol H2/1mol Zn)(6.022 X 1023/1mol H2) = 1.201 X 1023 molecules of H2 produced.
Zn+ H2O ---> ZnO + H2 Zn+ H2O ---> ZnO + H2
Zn + 2HCl --> ZnCl2 + H2
Zn (s) + 2HCl (aq) --> ZnCl2 (aq) + H2(g)
The equation is: Zn + 2HNO3 -----> Zn(NO3)2 + H2
The net ionic equation is Zn + 2H+ --> Zn2+ + H2
yes Zn + 2HCl -> ZnCl2 + H2 is balanced
Acid base reaction will occur when zinc oxide is added to nitric acid water and zinc nitrate (salt) are formed the equation is: ZnO + 2 HNO3 = Zn(NO3)2 +H2O
Zn + 2HCl >> ZnCl2 + H2 13.05 grams Zn (1mol Zn/65.41g Zn)(1mol H2/1mol Zn)(6.022 X 1023/1mol H2) = 1.201 X 1023 molecules of H2 produced.
Zn+ H2O ---> ZnO + H2 Zn+ H2O ---> ZnO + H2
Yes, according to the equation Zn (s) + 2HCl (aq) ----> ZnCl2 (aq) + H2 (g).
The balanced equation is as follows: Zn(s) + 2HCl(aq) --> ZnCl2(aq) + H2(g)
The reaction is: Zn + 2HCl = ZnCl2 + H2
A lot of that hydrochloric acrid is excess and some grams will not react, I think. Balanced equation first. Zn + 2HCl -> ZnCl2 + H2 Check to make sure of limiting reactant; I suspect zinc. 1.80 moles Zn (2 mole HCl/1 mole Zn) = 3.60 moles HCl You have a lot more than that, Zn limits and will drive the reaction 1.80 moles Zn (2 moles HCl/1 mole Zn)(36.458 grams/1 mole HCl) = 131 grams of hydrochloric acid reacted with that Zinc amount ----------------------------------------------------------------------------------