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Zn + 2HCl >> ZnCl2 + H2

13.05 grams Zn (1mol Zn/65.41g Zn)(1mol H2/1mol Zn)(6.022 X 1023/1mol H2)

= 1.201 X 1023 molecules of H2 produced.

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Q: How many molecules of hydrogen are produced if 13.05 g of Zn reacts with excess hydrochloric acid?
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