Complex ions are not the only ions that have color in solution. For example, Cu2+ is blue in aqueous solutions but is not a complex ion.
That's correct, but you haven't answer the question. Mn and Cu are transition metals that have d-orbitals available. One of the properties of the d-orbitals is that they can unfold and allow electrons to move freely in those unfolded orbitals. The energy the electrons lose is in the visible range of the spectrum, so we see it as colour.
Manganese in MnO4- is colored because it has unpaired d electrons in its d orbitals, leading to d-d transitions that absorb visible light. This absorption of light contributes to its purple color.
Due to charge transfer transition from oxygen to manganese.
The oxidation number for Mn in MnO4^- is +7. This is found by balancing the charges on the formula MnO4^- where O has an oxidation number of -2.
The oxidation number of oxygen (O) in MnO4 is -2. To find the oxidation number of manganese (Mn) in MnO4, we use the fact that the sum of the oxidation numbers in a compound is zero (since MnO4 is a polyatomic ion). Therefore, Mn must have an oxidation number of +7 in this compound.
For the MnO4- ion, the oxidation number of oxygen is typically -2. Since the overall charge of the ion is -1, the oxidation number of manganese (Mn) must be +7 to balance out the charges.
O.S. of Mn = +7 O.S. of O = -2 O.N. of cpd = -1
K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7
The oxidation number for Mn in MnO4^- is +7. This is found by balancing the charges on the formula MnO4^- where O has an oxidation number of -2.
The oxidation number of oxygen (O) in MnO4 is -2. To find the oxidation number of manganese (Mn) in MnO4, we use the fact that the sum of the oxidation numbers in a compound is zero (since MnO4 is a polyatomic ion). Therefore, Mn must have an oxidation number of +7 in this compound.
manganese is a metal element. It shows +4 in Mno4 ompouund.
Permanganate is a poly atomic ion, not an element. It contains two elements: manganese (Mn) and oxygen (O). The formula of the permanganate ion is MnO4-
For the MnO4- ion, the oxidation number of oxygen is typically -2. Since the overall charge of the ion is -1, the oxidation number of manganese (Mn) must be +7 to balance out the charges.
O.S. of Mn = +7 O.S. of O = -2 O.N. of cpd = -1
To balance the oxygens, you add H2O to one side, and the H^+ to the other (acid). Example:MnO4^- ===> Mn^2+ add 4 H2O to the right side MnO4^- ===> Mn^2+ + 4H2O this balances the oxygens. Now add 8H^+ to the left side MnO4^- + 8H^+ ===> Mn^2+ + 4H2O Now this is balanced for Mn, H and O. You now only have to balance the electrons (charge).
K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7
The chemical formula for manganese(II) superoxide is MnO2.
The permanganate ion is composed of one manganese atom (Mn) surrounded by four oxygen atoms (O) bonded together. The chemical formula of the permanganate ion is MnO4-.
In the anions of oxyacids, oxygen is always assigned an oxidation number of -2. Therefore, in an MnO4-1 anion, manganese must have an oxidation number of +7 to achieve electrical balance for the anion. (There is no neutral compound with the formula MnO4.)
The formula for hydronium permanganate is H3O+MnO4-.