[Ar] 3d2 4s2
It is [Ar] 4s2 3d2
The element is titanium and is in 4th period, group 4.
[Kr] 5s1
chromium (Cr) and copper (Cu)chromium has 4s1,3d5 instead of 4s2,3d4 and copper has 4s1,3d10 instead of 4s2, 3d9
[Ar]4s23d2
[Ar] 3d2 4s2
It is [Ar] 4s2 3d2
maybe you should put this question on wiki answers.com cause they have alot of intelegent people to answer these sorts of questions
The element is titanium and is in 4th period, group 4.
1s2 2s2 2p6 3s2 3p6 4s2 3d3A+
[Kr] 5s1
Titanium --------------------------> Ti4+ + 4e-[1s2, 2s22p6, 3s23p6] 3d2, 4s2 --->[1s2, 2s22p6, 3s23p6] + 4 electrons (from 3d and 4s orbital)Ti4+ is iso-electronic to Argon [1s2, 2s22p6, 3s23p6 ], the foregoing noble gas.
Period 4, Group 14 (= IV-A)Germanium, 32Ge, [Ar] 3d10 4s2 4p2 KLMN: (2, 8, 18, 4)Period 4, Group 4 (= IV) Titanium, 22Ti, [Ar] 3d2 4s2 KLMN: (2, 8, 10, 2)
[Ar] 3d2 4s2
chromium (Cr) and copper (Cu)chromium has 4s1,3d5 instead of 4s2,3d4 and copper has 4s1,3d10 instead of 4s2, 3d9
If you mean: 3d2+20d+12 then it is (3d+2)(d+6) when factored with the help of the quadratic equation formula