Because nitrogen forms a compound with hydrogen called anhydrous ammonia consisting of one nitrogen atom and three hydrogen atoms. Since hydrogen has an oxidation number of one, nitrogen must have an oxidation number of three to make a "neutral" molecule.
The oxidation number of NO, nitrogen oxide, is +3.
Nitrogen's oxidation number is -4.Carbon's oxidation number is +3.The cyanide ion has -1 charge. Nitrogen is in -3 state. By balancing the charges: the oxidation number of carbon is +4.
-3.
Nitrogen in -3
-3
In NF3, the element fluorine is more electronegative compared to nitrogen. The oxidation number of F in NF3 is -1. Lets assume then the oxidation number of N is x x + 3(-1) =0 x= +3 Oxidation number of Nitrogen in NF 3 is +3. In NI3, the element fnitrogen is more electronegative compared to iodine. The oxidation number of N in NI3 is -3. Lets assume then the oxidation number of I is y (-3) + 3y) =0 x= +1 Oxidation number of Iodine in NI3 is +1 Oxidation number of Nitrogen in NF 3 is +3. +3, as there is three halogens in each compund, therefore their oxidation number will add up to -3 and so to balance it out, nitrogen must be +3.
The oxidation number of NO, nitrogen oxide, is +3.
Nitrogen's oxidation number is -4.Carbon's oxidation number is +3.The cyanide ion has -1 charge. Nitrogen is in -3 state. By balancing the charges: the oxidation number of carbon is +4.
Nitrogen in -3
-3.
-3
It depends on the compound. Nitrogen has compounds in which the oxidation numbers range from -3 to +5.
It varies on the compound of nitrogen. -3 in nitrides is the most common. But oxidation number up to +5 is possible.
+3
+3 for each nitrogen in N2O3
Nitrosyl [NO+] has Nitrogen in +3 oxidation state and Oxygen in -2
Nitrogen has an oxidation number of -3. Since it is in group 15, it has 5 valence electrons. It wants to have eight, so it will gain three electrons. Electrons are negative, that's why the oxidation number is negative.