The electron withdrawing ability of the aromatic ring and its subsequent ability to delocalize the charge around the pi electron cloud of the ring, make the phenol Hydrogen fairly acidic. This reacts well with the alkaline sodium hydroxide. The H on the alcohol is not acidic.
yes
phenol are soluble in naoh because the reaction between phenol and naoh is exothermic and equilibrium lies to right that makes phenol stable.
sodium hydroxide is soluble becauce it is an alkali metal
no
Phenol is an acid while sodium hydroxide a base so it is acid base reaction forming the salt sodium phenoxide and water. C6H5-OH + NaOH = C6H5-ONa + H2O
yes
phenol are soluble in naoh because the reaction between phenol and naoh is exothermic and equilibrium lies to right that makes phenol stable.
No, sucrose is not soluble in sodium hydroxide without water.
sodium hydroxide is soluble becauce it is an alkali metal
Sodium bicarbonate is a solid, so no.
Ethanoic acid is fully soluble in water, but it will react with sodium hydroxide.
no
Sort of. Sodium oxide reacts with water to form sodium hydroxide, which is soluble.
Because in sodium hydroxide it forms phenoxide ion which is stabilized by solvolysis.
No, it is hardly soluble in sodium hydroxide though it is amphoteric. It's better in (hydrochloric) acid.
Phenol is an acid while sodium hydroxide a base so it is acid base reaction forming the salt sodium phenoxide and water. C6H5-OH + NaOH = C6H5-ONa + H2O
Phenol is not dissolved in a sodium hydroxide solution; having the characteristics of a weak acid phenol react with NaOH.