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Why is the centrifugal acceleration decrease from the equator to the poles?
Wiki User
∙ 7y ago
The relevant formula here is:
centrifugal acceleration = omega squared x radius
omega (the angular speed) doesn't change in this formula (for the situation under consideration), but "radius", the distance from the axis of rotation, does.
Wiki User
∙ 7y ago
Wiki User
∙ 7y agoThe centrifugal acceleration is proportional to the distance of the point from the axis of rotation. At the equator, it is the equatorial radius of the earth whereas the poles are on the axis of rotation so that the distance from the axis of rotation is zero.
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Is centrifugal force is more at equator than poles?
Yes, there is more centrifugal force near the equator than at the poles of the earth.
Why would an object way less at the equator than at the poles?
Not for sure but it seems like there would be more gravity at the equator than at the poles. The earth rotates and creates a centrifugal acceleration at the equator the counters the force of gravity. acceleration due to gravity =GM/R2 acceleration due to rotation =V2/R So gravity at the equator is GM/R2 - V2/R
Why is gravity stronger at the poles than the equator?
The closer an object gets to the center of the earth, the greater the pull of gravity on that object.
Why does the weight of an object change when it is moved from the equator to the poles?
Because of centripetal acceleration you will weigh a tiny amount less at the equator than at the poles.
Where is acceleration due to gravity greater?
It is greater at poles than at equator.
How the gravitational acceleration will change when you move from equator to north or south pole on the surface of earth?
It will increase very slightly at the poles compared to the equator, because the Earth's radius at the poles is slightly less than it is at the equator.
How does the earth rotation affect the measurement of the weight of an object at the equator?
Due to the centrifugal force caused by Earth's rotation opposing gravity for objects on the equator, objects there weigh about 0.5% less than they do on the poles. So an object that weighs 200 N at the poles weighs about 199 N on the equator.
Why does the weight of a substance changes when weighed in a diff parts of world?
it is because earth is not perfectly spherical and also it spins on its Axis. The centrifugal force is greater at the equator and zero on poles. So the apparent weight at equators is lee because of centrifugal force. Also Earth is flattened at the poles which means that there is more acceleration due to gravity at poles[since g=GM/(R^2] In all, ate value of g ranges from around 9.7-9.9 on earth. This causes all the difference.
What happenes to the temperature as one move from the equator to the poles?
temperatures starts to decrease in degrees and the days get shorter
What is the acceleration of a rock at the top of its trajectory when trown straight upward?
Assuming we are on the surface of the earth and we are dealing with humans of ordinary strength and abilities the acceleration is always 1g. Now the exact value of g varies slightly with to latitude due to the centrifugal force generated by the Earth's rotations. So it is about 10m/s2 at the poles and 9.81m/s2 near the equator.
Where should you stand on the earth's surface to experience the least centripetal acceleration Explain?
As the earth bulges a bit at the equator, you should stand at the poles to experience the most centripetal acceleration. Looking at the formula for centripetal acceleration (Ac= v2/r), we see that as the distance from the centre of the body (r) increases, the acceleration decreases, therefore when the distance to the centre mass is smaller, as it is at the poles compared to at the equator, the acceleration is greatest.
Does gravity have a stronger pull at the eatrh poles then it does on the equator?
no, but the electromagnetic field of the earth does.
