The relevant formula here is:
centrifugal acceleration = omega squared x radius
omega (the angular speed) doesn't change in this formula (for the situation under consideration), but "radius", the distance from the axis of rotation, does.
The gravitational acceleration will decrease slightly as you move from the equator to the poles due to the Earth's shape (oblate spheroid). This is because the centrifugal force is greater at the equator compared to the poles, which causes a slight decrease in the net gravitational force experienced at the equator.
No, centrifugal force is greater at the poles than at the equator because the Earth's rotation causes a bulging effect at the equator that counteracts the centrifugal force. This is why objects weigh slightly less at the equator compared to the poles.
Not for sure but it seems like there would be more gravity at the equator than at the poles. The earth rotates and creates a centrifugal acceleration at the equator the counters the force of gravity. acceleration due to gravity =GM/R2 acceleration due to rotation =V2/R So gravity at the equator is GM/R2 - V2/R
Yes, there is a difference in the value of acceleration due to gravity (g) at the equator and the poles. This is because the Earth is not a perfect sphere and has an oblate shape. At the equator, the centrifugal force due to the Earth's rotation reduces the effective gravity and makes g slightly smaller compared to the poles where this effect is minimal.
The value of acceleration due to gravity (g) decreases as you move from the Equator towards the poles due to the centrifugal force caused by the Earth's rotation. At the Equator, this force counteracts some of the gravitational force, resulting in a lower g value compared to the poles.
Yes, the maximum value of acceleration due to gravity (g) is at the equator because the centrifugal force due to the Earth's rotation reduces the effective gravitational force. This results in a maximum g value at the equator compared to other latitudes.
Gravity is stronger at the poles than the equator because of the Earth's shape. The Earth is an oblate spheroid, meaning it is slightly flattened at the poles and bulges at the equator due to its rotation. This bulging at the equator causes objects to be farther away from the center of the Earth, resulting in weaker gravitational pull compared to the poles.
1 kg of sugar will weigh slightly more at the poles compared to the equator due to differences in gravity caused by the Earth's rotation. Gravity is stronger at the poles and weaker at the Equator due to the centrifugal force caused by the Earth's rotation.
say mass(m) = 100 kgvelocity(v) at equator = 464.6 metres / secondradius(r) to earth surface = 6 371 000 metresacceleration due to gravity (g) = 9.82 (m / s) / s.the force of attraction (f) anywhere on earths surface, = m * g = 100 * 9.82 = 982 newtons.the force of repulsion / centripetal force (f) at the equator = mass * (v^2) / r =3.39 newtons
used by spinning motion of the earth around its axis passing through the poles...the force being max at the equator...since at tym of formation, earth was in fluid state, the force of cohesion was small & could not balance the centrifugal force...hence it bulged out at the equator
Water expands at the equator due to the centrifugal force caused by the Earth's rotation. This force effectively bulges the water in that region, resulting in a slightly larger volume compared to water at the poles.
The weight of an object changes when it is moved from the equator to the poles due to the variation in gravitational force caused by the Earth's rotation. The force of gravity is slightly stronger at the poles compared to the equator, leading to a small change in weight.