I am not sure how the two objects of equal resistance are supposed to be connected. But for a current to flow, for example across a resistor, there must be a voltage difference between the terminals of this resistor.
A physical phenomenon produced by the motion of electric charge, resulting in attractive and repulsive forces between objects.
Air resistance decreases acceleration of falling objects
Electric and magnetic forces are transmitted via photons.
we use to much electric objects
The resistance of an objects surroundings to its motion. The rugs nape versus a ball rolling across it. Air having to get out of the way of a spinning tennis ball. Resistance. Of course gravity can have a positive or negative influence on an objects motion and vector. Entropy concurs all motion.
Think of it like this: Friction causes you difficulty in pulling heavy objects on a carpet. This frictional force is similar to electrical resistance. It is one of two ways to define how easily electricity will travel through an electrical element.
The higher the current, the more heat generated. Also, the smaller the diameter of the wire, the higher the heat. It is important to choose the correct amperage rating of the wire to prevent fires.Another AnswerThe work done by an electric current is the product of the square of that current, and the resistance of the conductor. The resulting heat depends upon the difference between the temperature of the conductor and that of the surrounding air. Remember, heat is defined as the transfer of energy between objects at different temperatures.
The electric force between two charged objects is influenced by the distance between them.
electric current
Electric Force is the force between charged objects.
weaker as square of distance
Mass certainly affects the gravitational attraction between objects; air resistance doesn't.
This is false. The answer is that mass and distance affect the gravitational attraction between objects. Air resistance has no effect on this.
The electric force between two charged objects is decreased by a factorof 4 if you double the distance between the objects, from the formulaF=(q1*q2)/(4*Pi*Eo*r^2).
The electric force between two charged objects is decreased by a factorof 4 if you double the distance between the objects, from the formulaF=(q1*q2)/(4*Pi*Eo*r^2).
electric force.
-- the product of the magnitudes of the charges on the objects -- the distance between the 'center of charge' of the two objects