Maybe because Sun said so. We have to bear with so many other idiosyncrasies too. But I guess that comes with every language.
There were two major reasons why operator overloading wasn't allowed in Java: "cleanliness" and compiler complexity. The main reason was the first, a personal preference choice made by Java's creator, James Gosling.
Operator overloading, while useful, can be exceedingly confusing, much more so than method overloading. Given the human tendency to assign specific meanings to single symbols, it is hard to get programmers to wrap their heads around multiple meanings for operators. What this means is that there is a marked increase in programming errors when a language supports operator overloading. Since practically the same benefit can be obtained via methods, the Java designers decided that the increased programmer mistake rate was not worth supporting operator overloading.
From a Java compiler (e.g. javac) design standpoint, supporting operator overloading is considerably more difficult than method overloading, requiring a more complex compiler.
Java does not support opperator overloading, so the answer to your question is: none.
Java does not support user defined operator overloading.The operator '+' is overloaded in Java and can be used for adding both numbers and Strings.
Java does not support object overriding. It does support operator overloading by means of the "+" symbol which is used for both numeric addition as well as string concatenation.
== == === === === === === === Some Body told me that operator overloading is not there because it violates the transparency of java.since there is no hiding of information in java it does support op overloading === === === === === === Pranab Kumar Rana Software Engineer..... === === === ===
C does not support operator overloading. If you mean C++ operator overloading, it depends on exactly what you wanted to do. If you wanted to '+' to strings, then you could write: string operator+(string a, string b) { // do something }
I think you mean operation overlord??? It is the American, Canadian and British offensive on Europe in World War 2. They landed in Normandy on 6th June 1944 (Commonly called D-Day, Day of Days or Deliverance Day) and progressed throughout France liberating Paris on the 25th August. This allowed the allies a foothold in Europe.
Pressumably, the designers of Java thought this would lead to confusing code.
No. Operator and/or function overloading is only a C++ thing.
You cannot create a new operator through operator overloading. You can only redefine an existing operator, with certain limitations. As an example, for a class of complex numbers, having a real and an imaginary part, you might want an addition operator. This is the skeleton of code to do that. I only show the operator, not any constructors or other operators or methods, etc.class complex {private:double real, imaginary;public:complex operator+ (complex operand) {complex temp;temp.real = this.real + operand.real;temp.imaginary = this.imaginary + operand.imaginary;return temp;}};The above answer is for C++. Since this question is also categorized in Java Programming it's important to note that operator overloading is not currently possible in Java.
JAVA is an Object Based Programming Language. it doesn't provide multiple inheritance and operator overloading. while Object Oriented Lanuages provides both.
The assignment is done explicit without internal operation. Subject to the programming language, explicit assignment operators are needed wherever implicit ones are insufficient. Implicit assignment is typically implemented as a flat copy, while explicit overloading of the assignment operator allows for any other suitable behavior. Consider this example in pseudocode similar to C++: class Demo { int* valuepointer; ... }; Demo a, b; ... b = a; Assigning a to b using implicit assignment means that a.valuepointer and b.valuepointer share the same value. Both a and b can change the pointed-to value, and the either will "see" the change. This is the required behavior in some cases, but often, you'd want to explicitly assign a to b such that each has its own pointer, accessing different copies of the value. This behavior would require an explicit assignment operator (or copy constructor).
Function overloading is multiple definition with different signatures(the parameters should be different) for the same function. The parameter list have to be different in each definition. The compiler will not accept if the return type alone is changed. Operator overloading is defining a function for a particular operator. The operator loading function can not be overloaded through function overloading.