Because the material does not disappear, it breaks down to another material.
And in the process relases some radiation.
No. In two half-lives, a radioactive isotope will decay to one quarter of its original mass. In one half-life, one half of the mass decays. In the next half-life, one half of the remaining mass decays, and so on and so forth. At each half-life point, you would see 0.5, 0.25, 0.125, 0.0625, etc. remaining. The logarithmic equation is... AT = A0 2(-T/H)
If the half-life of a nuclide is 44.5 days, then 178 days is four half-lives. After four half-lives, 0.0625 (0.54) of the original nuclide remains. If 50g is the original mass, then the mass after 4 half-lives is 3.125g. AT = A0 2(-T/H) A178 = (50) 2(-44.5/178) A178 = 3.125
Half life has unit. That is unit of time. So it has to be mentioned. Let us assume that half life is 1 year. Okay. Now to know about the mass remaining we have to get the ratio (1/2)^1620. Hence remaining will be 1/(2^1620) * mass at the beginning
If you take one day equal to 24 hours, then 1 day constitutes 2 Half lives. Mass of isotope left after 12 hours=10/2=5g Mass of isotope left after 2 half lives or 1 day=5/2=2.5g.
18 days
1.48 * If 0.0105 g of a radioisotope remained after six half-lives, then the original mass was 0.672g.
.0463g*25 =1.4816g
I think it´s mass.
0.672
3.79
No. In two half-lives, a radioactive isotope will decay to one quarter of its original mass. In one half-life, one half of the mass decays. In the next half-life, one half of the remaining mass decays, and so on and so forth. At each half-life point, you would see 0.5, 0.25, 0.125, 0.0625, etc. remaining. The logarithmic equation is... AT = A0 2(-T/H)
A half-life is the amount of time it takes for half of the material to decay. So if you started with 80g After 1 half-life you would have 40 g After 2 half-lives you would have 20 g After three half-lives you would have 10 g
A radioactive substance halves in size and activity after every period of time that is defined as its half-life, decaying into its constituent products. Therefore, the mass of the radioactive substance after x half-lives is as follows:Mass = 0.5x x original mass.Using this formula, the original mass is 4.00g and the number of half-lives is 6 (9/1.5 = 6). We therefore have a mass of 4 x 0.56 g, which is equivalent to 1/16 of a gram.
The half-life of an atom is how long it takes for half of the atom's mass to radioactively decay. This occurs exponentially; therefore, after 2 of the atom's half-lives have passed, 3/4 of the atom will have decay (half during the first half-life, then half of the remaining mass, or one quarter, during the second).
Depends on how many grams you started with, but obviously if half decays, half is left.
Half life is the time taken for half the atoms to decay. Whatever mass you start with, if it is a sample consisting of one pure uranium isotope, you will have half that mass of uranium after one half life. The piece of metal will not weigh half of the original mass, because the decay products will be there. In practice, a piece of uranium usually consists of a mixture of isotopes with different half lives.
If the half-life of a nuclide is 44.5 days, then 178 days is four half-lives. After four half-lives, 0.0625 (0.54) of the original nuclide remains. If 50g is the original mass, then the mass after 4 half-lives is 3.125g. AT = A0 2(-T/H) A178 = (50) 2(-44.5/178) A178 = 3.125