The crystal oscillator frequency in the Intel 8085 is divided by 2 because Intel designed it that way. Internal actions in the 8085 occur at various points in the cycle and, by dividing by 2, Intel could create 4 distinct points in the cycle where various edges could perform actions.
Because that's how Intel designed it. They wanted an internal four phase clock, so the most logical way was to divide the crystal oscillator frequency by two. Different things happen at different clock edges, and they accomplished their goal.
to get more acuracy and not to change according to time and other factors we divide the clock frequency
we can use rc or lc oscillators also but crystal oscillator makes it to have longer life time
crystal is a oscilltor in microprocessor
The clock out frequency of an 8085 is one half the crystal frequency. The period of one T cycle is the inverse of the clock frequency. At a crystal frequency of 5MHz, the clock is 2.5MHz, and T is 400 ns.
At a crystal frequency of 6MHz, the 8085 microprocessor has a clock frequency of 3MHz, or a period of 333 nanoseconds. The NOP instruction requires four clock cycles, three to fetch and one to execute, so the NOP instruction with a crystal frequency of 6MHz would take 1.333 microseconds to fetch and execute. This does not include wait states, each of which would add 0.333 microseconds to the timing.
it has high stability large q factor and the frequency that doesn't drift with aging. It is used as a clock source most of the times.
The operating frequency of 8085 is 3 mhz to 5 mhz
all the operations of microprocessor are carried out at active edge,it can either be a rising edge or falling edge.that's why freq. gets havled
The CLK signal in the 8085 is the system clock, which is the External Input Frequency or Crystal divided by two. It can be used to develop bus control logic, because it is essentially the inverse of ALE for one half clock cycle.
In order to determine the instructions per second in an 8085 microprocessor, you need to know how long each instruction takes to execute. Some are as short as 4 T cycles. Some are as long as 18 T cycles. This is dependent on how the program is written. Add up the T cycles for each instruction. Divide the clock frequency in hertz by the number of T cycles, and you get instructions per second. Note that clock frequency is one half of the crystal frequency. Note also that you must include Twait cycles in your calculation.
microprocessor 8085 is basic 8 bit microprocessor by Intel Corp. it has 64Kb memory and 16 address buses and 8 data buses it has 40 pin ic. 8 address and 8 data buses are multiplexed with each other for reducing the total number of pins from the microprocessor 8085 . it require 5MHz clock frequency for operation. only a crystal which connected easily across two pins of microprocessor can provide this clock.
that depends on the microcontroller. check the datasheet.
that varies depending on the microprocessor used.
At the very heart is a piece of crystal that vibrates at a very precise frequency when an electric potential is placed across it. The microprocessor counts these pulsations and there-by keeps time. The microprocessor utilizes a binary counter which is a collection of transistors arranged into logical devices and memory storage units that keep track of the logical progression of the counting.