Want this question answered?
That's not true. The molar volume of a gas is always greater than the molar volume of a liquid. I can't think of any exceptions to this.
Molar gas volume is the volume of ONE moel of gas. It only depends on the pressure and temperature, not on the kind of gas. Molar volume at standard temperature and standard pressure is always 22,4 Litres (for any gas)
Empirical formula = C3H5O Molar mass of empirical formula = 3(12.01)+5(1.008)+1(16) = 57.07 Molar mass of molecular fomula = 114.15 n = Molar mass of molecular fomula/Molar mass of empirical formula = 114.15/57.07 n = 2 Molecular formula = n(empirical formula) Molecular formula = 2(C3H5O) = C6H10O2 Check: 6(12.01)+10(1.008)+2(16)= 114.14
C7h6o2
MgCO3 has a molar mass (molecular weight) of 84.3139 g/mol.
parachor is depend on the surface tention of the liquid and its molar volume rheocor is depend upoun the viscosity of a liquid . both are additive and constiitutive property.
Parachor is a quantity relating the surface tension to the molecular weight and density. It is defined by the formula (surface tension ^1/4) * M / d. Parachor is used in solving structural problems. Sugden defined in 1924 parachor as (surface tension in mN/m)^(1/4).(molar volume in cm^3/mol). This definition is used up to now and it results in usual parachor values of the order of magnitude of 100. Therefore, parachor is a derived quantity like any other and its unit is (mN/m)^(1/4).cm^3/mol. This unit is so bizare in the light of usual experience that most authors do not dare give it in their texts and prefer not to give any unit. Owing to this fact, there has arisen the mistaken impression that the parachor has no unit. S. Sugden, J. Chem. Soc. Trans. 125 (1924) 1167--1177, from contemporary literature see M. Souckova et al. J. Chem. Thermodynamics 83 (2015) 52-60
A parachor is a constant for a liquid that relates the surface tension to the molecular volume. The formula is P = y^(1/4)(M/d) where y is the 4th root of the surface tension. M is the molar mass, and d is the density.
Molecular weight (unit) of salt dissolved in liter (unit) volume of water.
grams divided by the molecular weight to get to moles moles divided by volume to get molarity
Molar Behavior : The behavior which we observe as a whole is known as molar behavior. Molecular Behavior : The behavior which we can observe part by part is known as molecular behavior
That's not true. The molar volume of a gas is always greater than the molar volume of a liquid. I can't think of any exceptions to this.
The atomic (molecular) weight of a substance is its molar mass.
Sugden defined in 1924 parachor as P=(surface tension in mN/m)^(1/4).(molar mass in g/mol).(density in g/cm^3), which is equivalent to (surface tension in mN/m)^(1/4).(molar volume in cm^3/mol). This definition is used up to now and it results in usual parachor values of the order of magnitude of 100. Therefore, parachor is a derived quantity like any other and its unit is (mN/m)^(1/4).cm^3/mol. This unit is so bizare in the light of usual experience that most authors do not dare give it in their texts and prefer not to give any unit. Owing to this fact, there has arisen the mistaken impression that the parachor has no unit. Sugden showed empirically that P is additive with respect to the composition of molecules of compounds from different atoms and atomic groups. As a result, when the values of the contributions to parachor from the individual atomic groups of molecules are known the surface tension of substances can be evaluated from their molecular structure. S. Sugden, J. Chem. Soc. Trans. 125 (1924) 1167--1177, from contemporary literature see M. Souckova et al. J. Chem. Thermodynamics 83 (2015) 52-60
molar mass of unknown/molar mass of empirial = # of empirical units in the molecular formula. Example: empirical formula is CH2O with a molar mass of 30. If the molar mass of the unknown is 180, then 180/30 = 6 and molecular formula will be C6H12O6
I'm not exactly positive. But if you know the volume in grams and the mass (giving you density), then you should be able to figure out the molecular weight. The mass is the same as the molar mass, which I would assume is the same as the molecular weight, but I'm not positive.
N10H20Cl10