The sulfur is present as the [S2]2- ion iron is present as iron(II). The average ox # of S is therefore -1
The S valence would be -1 when Fe(II) is 2+. In most cases sulfur has one negative and two possible positive valences: -2 and +4 or +6. So FeS2 is not a possible, or maybe a very rare, compound (Iron(II) persulfide?).
The oxidation number of S in S2Cl2 is +1. Each Cl atom has an oxidation number of -1, and since the molecule is neutral, the overall oxidation numbers of S must balance out to zero. Thus, the oxidation number of S in this compound is +1.
the 2 in FeS2 means there are 2 sodium atoms and one iron atom
In FeSO4, the oxidation number of Fe is +2, and the oxidation number of oxygen is -2. To find the oxidation number of S, we can set up an equation: 2(-2) + x + 4(-2) = 0 (overall charge of the compound is zero). Solving this equation gives the oxidation number of S as +6.
The oxidation number of H in NaHSO4 is +1. In this compound, Na has an oxidation state of +1, S has an oxidation state of +6, and O has an oxidation state of -2. By adding up the oxidation states and solving for H, it is determined to be +1.
The S valence would be -1 when Fe(II) is 2+. In most cases sulfur has one negative and two possible positive valences: -2 and +4 or +6. So FeS2 is not a possible, or maybe a very rare, compound (Iron(II) persulfide?).
The oxidation number of S in S2Cl2 is +1. Each Cl atom has an oxidation number of -1, and since the molecule is neutral, the overall oxidation numbers of S must balance out to zero. Thus, the oxidation number of S in this compound is +1.
the atomic mass of FeS2 is 110. You cannot find the no. of moles in a mole of FeS2 coz it is only a mole.
the 2 in FeS2 means there are 2 sodium atoms and one iron atom
the Atomic Mass of FeS2 is 110. You cannot find the no. of moles in a mole of FeS2 coz it is only a mole.
In FeSO4, the oxidation number of Fe is +2, and the oxidation number of oxygen is -2. To find the oxidation number of S, we can set up an equation: 2(-2) + x + 4(-2) = 0 (overall charge of the compound is zero). Solving this equation gives the oxidation number of S as +6.
The oxidation number of H in NaHSO4 is +1. In this compound, Na has an oxidation state of +1, S has an oxidation state of +6, and O has an oxidation state of -2. By adding up the oxidation states and solving for H, it is determined to be +1.
The oxidation number of NCS is -1. N has an oxidation number of -3, while S has an oxidation number of +6 in the NCS molecule.
+1 for H +6 for S -2 for each O
The oxidation number of Na in Na2S is +1. The oxidation number of S is -2. The sum of the oxidation numbers of all atoms in a compound must equal zero.
The oxidation number of S in HSO3- is +4. This is determined by assigning a -1 oxidation state to the hydrogen atom and a -2 oxidation state to the oxygen atoms, which leaves sulfur with a +4 oxidation state to balance the overall charge of -1 for the ion.
The oxidation state of K in K2O2 is +1. In this compound, each K atom has a +1 oxidation state and each O atom has a -1 oxidation state.