Want this question answered?
It becomes a nucleophile.So it can participhate in electrophilic reactions.
methanol. CH2O > The hydride forms a bond with the anti bonding orbital of the carbonyl carbon and oygen pi bond, which breaks, THe filled antibond orbital, is then a sigma bond, and occured during reduction via a HYDRIDE acting as a nucleophile. THIS leaves CH3O- A methoxide, which is extremely reactive, and upon work up, forms an alcohol. METHANOL.
An alcohol, but it has cyclic rings and double bond.
A secondary alcohol undergoes oxidation to yield a ketone; a primary alcohol forms an aldehyde instead, and a tertiary alcohol usually does not form either a ketone or an alcohol, because the carbon having the OH group in a tertiary alcohol already has three bonds to other carbon atoms and therefore cannot form a double bond to oxygen without more extensive breaking of other bonds in the tertiary alcohol.
Nitrogen is a diatomic gas at room temperature. These nitrogen atoms are bond by a triple bond. It needs more energy to break this bond. So nitrogen is less reactive.
It becomes a nucleophile.So it can participhate in electrophilic reactions.
methanol. CH2O > The hydride forms a bond with the anti bonding orbital of the carbonyl carbon and oygen pi bond, which breaks, THe filled antibond orbital, is then a sigma bond, and occured during reduction via a HYDRIDE acting as a nucleophile. THIS leaves CH3O- A methoxide, which is extremely reactive, and upon work up, forms an alcohol. METHANOL.
No, they are not likely to bond. Neon has a complete octet and is not reactive.
according to some sources , Urea breaks all bond except for covalent bond , which means the secondary structure will remain , and also the primary structure with peptide bond.
Possibly not as gold is not very reactive. If they did bond it would be ionic.
In a primary (1°) alcohol, only attached to one alkyl group; In a secondary (2°) alcohol, attached two alkyl groups & tertiary (3°) alcohol, attached three alkyl groups Actually, that person has you more confused. This is an easy way to remember what is 1 degree, 2 degree or 3 degree of Alcohols. 1 degree: R-- CH2 -- OH 2 degree: R2 -- CH -- OH 3 degree: R3 -- C -- OH R = CH3
Because the double bond between nitrogen is very strong
no
Nitrogen Is Uncreative beacuase of the triple bond between 2 nitrogen atom,which have a bond enthalpy of 945kjmol-1,and this result for a fewer reactions of nitrogen.
Metallic bond is the reaction between molecules within metals, called alkali reactive force.
Ether Bond
Yes. Fluorine is extremely reactive, it has a weak F-F bond and readiliy forms the F- ion