Newton wrote that force is equal to the rate of change of momentum. This isF = dp/dt (1). As momentum, p, is the product of mass, m, and velocity, v,(1) is equivalent to F = dmv/dt (2). Velocity is the rate of change of position,and becomes acceleration under differentiation with respect to time. Applyingthe product rule to (2) gives F = vdm/dt + mdv/dt. Unless a body's mass ischanging (e.g. ejecting fuel to take off, or moving at relativistic speeds),dm/dt = 0. So (2) becomes F= mdv/dt. But dv/dt is the acceleration, a.So we can see that F = ma.
Pressure is the force that launches the bottle rocket once it has launched this pressure starts to dissipate until no other force is driving the rocket to overcome gravity, therefore gravity is now the only force acting on the object and as such the bottle falls back to earth
The induced emf ie voltage in a conductor or coil is directly proportional to the rate at which the magnetic flux linked with it changes. So when the speed is less then dB/dt will be less and so induced voltage becomes less. If the speed is high then dB/dt will be very much high and so large emf will be induced.
Change in temperature, dT,=1/m, where m is the amount of water, in kilograms. Depends on how much kilograms of water you have. The equation to use is Q=cm(dT), where c is the specific heat capacity of water (conventional use puts it 4186 J/(kg*C degrees)), m is the mass, in kilograms, of the water you're heating, dT is the amount of degrees, in Celsius (or Kelvin), that you want to heat the water by, and Q is the amount of energy needed, in Joules. 1 kilocalorie equals 4186J, solving for change in temperature (dT), dT=Q/(cm). Substituting in Q and c gives you dT=1/m. If you do not know the mass, but only volume, m=pV, where p is the density of water (convetionally 1 *10^3 kg/m^3) and V is the volume of the amount of water you have in m^3.
Depends on the equation. If it is similar to: Q = m*Cp*dT then Q = energy if it is similar to A= Ao * exp (-Q/RT) then Q is the activation energy
It is important to wear safety goggles in any situation where flying objects or splashing corrosive or toxic liquids could strike and damage your eye. The reason for this is that the loss or significant impairment of vision in one or both eyes usually results in a catastrophic change in your quality of life, not to mention the pain and expense involved in the short term. There are a variety of "safety goggles" designed to offer some degree of protection against different types of hazards to the eye.
never do something without a teacher
DT can mean several things:Damage and Tolerance- in which case a DT engineer would measure wear and tear on products and suggests remediesDrive Testing- in which case a DT engineer would drive a vehicle (or any product) to test it.Or any one of about 100 other things...
Northface hyvent dt i believe
Rockets work on the conservation of vector energy, cP. 0 = dcP/dr = cdP/cdt=dP/dt = d(mV)/dt = mdV/dt + Vdm/dt=0 Thus, mdV/dt = -Vdm/dt, or (dV/dt)/V = -(dm/dt)/m. The Rocket's mass accelerates at the rate of the mass changes dm/dt.
d/dt cot (t) dt = - cosec2(t)
a = dv/dt =d(vet)/dt =dv/dt *et+det/dt *vwith det =...
The formula for the volume of a cube is V=s^3. Take the first derivative----> d/dt(V)= d/dt(s^3) ---->dv/dt= 3s^2 (ds/dt) dv/dt is the propagated error for volume, so the other variables should already be defined in the question where: s= side length and ds/dt would equal possible error in each side. Sometimes it's necessary to solve for these variables using other formulas the most common of which is surface area which is: SA=6s^2 where SA`= dsa/dt= 12s (ds/dt).
<dl> definition list <dt></dt> definition tag <dd></dd> data definition <dt></dt> <dd></dd> </dl>
Yes, dD/dt = d0/dt = 0 thusDisplacement D=0 and Velocity dD/dt=d0/dt = o.
y=x3+ 2x, dx/dt=5, x=2, dy/dt=? Differentiate the equation with respect to t. dy/dt=3x2*dx/dt Substitute in known values. dy/dt=3(2)2 * (5) dy/dt=60
KCGE-DT was created in 2003.