solution containig (3.3)gm na2co3 .h2o in (15ml)
The chemical formula of sodium carbonate is Na2CO3. A solution hasn't a formula.
Na2CO3 +H2O----->HCO3++OH-HERE HCO3- IS A WEAK ACID AND OH- IS A STRONG BASE
na2co3 is more basic nahco3 is more acidic but both are bases.
Because it contains sodium cations, which are strongly basic, and carbonate anions which are weakly acidic. So the basic ions win over acidic ions, making Na2CO3 alkaline(i.e. basic).
Red litmus paper turn blue in basic solutions; sodium carbonate solution is basic.
solution containig (3.3)gm na2co3 .h2o in (15ml)
The chemical formula of sodium carbonate is Na2CO3. A solution hasn't a formula.
Na2CO3 +H2O----->HCO3++OH-HERE HCO3- IS A WEAK ACID AND OH- IS A STRONG BASE
na2co3 is more basic nahco3 is more acidic but both are bases.
Because it contains sodium cations, which are strongly basic, and carbonate anions which are weakly acidic. So the basic ions win over acidic ions, making Na2CO3 alkaline(i.e. basic).
Did you mean 250 mL of 0.15 M Na2CO3? (It's impossible to make a 15 M Na2CO3 solution, as Na2CO3 is not that soluble.) Yes, you can assume that this will be an aqueous solution. Steps. 1. Calculate the mass of solid Na2CO3 needed. 2. Place this mass of Na2CO3 in the volumetric flask. 3. Add some water and swirl to dissolve the Na2CO3. 4. Carefully add more water until the total volume of solution is 250 mL, as indicated by the line etched on the neck of the volumetric flask. 250 mL x 1 L x 0.15 mol Na2CO3 x 105.99 g Na2CO3 = 4.0 g Na2CO3 needed ........... 1000 mL ......... 1 L ..................1 mol Na2CO3
You need to mention the unit for 2,61.
MgCl2 + Na2CO3 = 2NaCl + MgCO3
Sodium carbonate is added with the purpose to increase the pH of the solution.
yes it is
The solution must contain Na2CO3 and NaHCO3.