To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of Na2CO3 (sodium carbonate) is 105.99 g/mol. So, to find the grams in 0.577 mol of Na2CO3, you would calculate 0.577 mol * 105.99 g/mol = approximately 60.98 grams of Na2CO3.
The AR (atomic mass) of CO2 (carbon dioxide) is 44 g/mol. The MR (molar mass) of Na2CO3 (sodium carbonate) is 106 g/mol.
0.277 mole Na2CO3 x 106 g/mole = 29.4 g (to 3 significant figures)
Na2CO32 * 2 = 4 moles sodium.===========================
The molar mass of Na2CO3 is approximately 105.99 g/mol. When 2.61 g of Na2CO3 is dissolved in 250 mL of solution, the molarity of the solution is calculated as (2.61 g / 105.99 g/mol) / (250 mL / 1000) = 0.0984 M.
To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of Na2CO3 (sodium carbonate) is 105.99 g/mol. So, to find the grams in 0.577 mol of Na2CO3, you would calculate 0.577 mol * 105.99 g/mol = approximately 60.98 grams of Na2CO3.
The AR (atomic mass) of CO2 (carbon dioxide) is 44 g/mol. The MR (molar mass) of Na2CO3 (sodium carbonate) is 106 g/mol.
The molar mass of Na2CO3 is 106 g/mol. The molar mass of sodium in Na2CO3 is 2 * 23 g/mol = 46 g/mol. To calculate the mass percent of sodium in Na2CO3, we divide the molar mass of sodium by the molar mass of Na2CO3 and multiply by 100: (46 g/mol / 106 g/mol) * 100 ≈ 43.4%.
The mass of 7 050 moles of natural uranium is 238,02891 x 7 050.
0.277 mole Na2CO3 x 106 g/mole = 29.4 g (to 3 significant figures)
Washing soda is sodium carbonate, Na2CO3. Using the atomic weights from the periodic table and the subscripts in the formula, the molar mass of Na2CO3 = 106g/mol. 5g Na2CO3 x (1mol Na2CO3/106g/mol) = 0.05mol Na2CO3
Na2CO32 * 2 = 4 moles sodium.===========================
The molar mass of Na2CO3 is approximately 105.99 g/mol. When 2.61 g of Na2CO3 is dissolved in 250 mL of solution, the molarity of the solution is calculated as (2.61 g / 105.99 g/mol) / (250 mL / 1000) = 0.0984 M.
The molar mass of sodium carbonate (Na2CO3) can be calculated by adding the atomic masses of its constituent atoms. The atomic mass of Na is approximately 23 g/mol, C is approximately 12 g/mol, and O is approximately 16 g/mol. Therefore, the molar mass of Na2CO3 would be: 2(23) + 12 + 3(16) = 106 g/mol. Rounded to the nearest gram, the molar mass of sodium carbonate is 106 g/mol.
4.25 grams. .050 M = .050 mol/1 L 5.0 L x .050 mol/L (cancel out L to get mol as a unit)= .25 mol Atomic mass of Ammonia (NH3)= 17 g/mol .25 mol x 17 g/mol (cancel out mol to get g as a unit)= 4.25 g
the answer to your question is 0.0004 g/mol.
To determine how many moles of Na2CO3 are used, you need to know the molar mass of Na2CO3. It is 105.99 g/mol. Then, you can calculate the number of moles using the given mass: mass in grams / molar mass = moles of Na2CO3.