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Tertiary amines have alkyl groups around the central atom (nitrogen) while ethanol has hydrogen atoms and one hydroxyl group around the carbon atoms. As a result, ethanol is more prone to attack by other groups while in tertiary amines, stearic hindrance doesn't allow attack of incoming groups. So, tertiary amines are more stable than ethanol.
the hybrdization of allyl radical carbon is sp2 which overlaps with the p orbitals of the alkene
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The reason is that the aryl group is able to stabalize the diazonium salt through resonance, while the alkyl group may not be resonance stabalized.
Yes an alkyl halide can undergo both Sn1 and Sn2 reactions - it just depends on what kind of alkyl halide it is. Methyl halides such as CH3Br/CH3Cl/CH3I, etc. are most suitable for Sn2 reactions because they are less sterically hindered by R-groups (they are not "bulky"). This allows for easy attack by the nucleophile. Primary alkyl halides (RCH2X) are also most suitable for Sn2 because of the same reason above Secondary alkyl halides can undergo both Sn1 and Sn2 reactions, this depends on other factors such as solvent and leaving group and nucleophile. If the solvent is polar aprotic, the reaction will go Sn2, if polar protic - Sn1. Tertiary alkyl halides (alkyl halides with 4 r-groups) do not go Sn2 because they are bulky and the R-groups stabilize the carbocation by hyperconjugation and inductive effect.
The Wurtz reaction is not suitable for tertiary alkyl halides due to side reaction involving elimintaion reactions.
Tertiary amines have alkyl groups around the central atom (nitrogen) while ethanol has hydrogen atoms and one hydroxyl group around the carbon atoms. As a result, ethanol is more prone to attack by other groups while in tertiary amines, stearic hindrance doesn't allow attack of incoming groups. So, tertiary amines are more stable than ethanol.
Tertiary alcohols have a bulky alkyl group bonded to the carbon atom that carries the hydroxyl group. This bulky group hinders the approach of the sodium atom, making the reaction less rapid. In contrast, primary alcohols have a smaller alkyl group and allow for easier access and reaction with metallic sodium.
the hybrdization of allyl radical carbon is sp2 which overlaps with the p orbitals of the alkene
An aralkyl is a univalent radical derived from an alkyl radical by replacing one or more hydrogen atoms by aryl groups.
An alkylamino is a group or radical which contains both an alkyl and an amino group.
An arylalkylamine is a secondary or tertiary amine which has both an alkyl and an aryl group connected to the nitrogen atom.
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If u are referring to the carbocations of n-butyl, sec-butyl, and t-butyl, the most stable is the one that has the most alkyl groups attached to the positively charged carbon atom. In this case: - n-butyl has only 1 alkyl group attached - sec-butyl has 2 alkyl groups attached - t-butyl has 3 alkyl groups attached Therefore, t-butyl is the most stable carbocation
An alkoxy is any univalent radical R-O- or anion R-O-, where R is an alkyl group.
The reason is that the aryl group is able to stabalize the diazonium salt through resonance, while the alkyl group may not be resonance stabalized.
Yes an alkyl halide can undergo both Sn1 and Sn2 reactions - it just depends on what kind of alkyl halide it is. Methyl halides such as CH3Br/CH3Cl/CH3I, etc. are most suitable for Sn2 reactions because they are less sterically hindered by R-groups (they are not "bulky"). This allows for easy attack by the nucleophile. Primary alkyl halides (RCH2X) are also most suitable for Sn2 because of the same reason above Secondary alkyl halides can undergo both Sn1 and Sn2 reactions, this depends on other factors such as solvent and leaving group and nucleophile. If the solvent is polar aprotic, the reaction will go Sn2, if polar protic - Sn1. Tertiary alkyl halides (alkyl halides with 4 r-groups) do not go Sn2 because they are bulky and the R-groups stabilize the carbocation by hyperconjugation and inductive effect.