Br2 + C2H4 → C2H4Br2 OR
Br2 + CH2=CH2 → BrCH2CH2Br
The name of the reaction is pretty intuitive. Ethene's double bond is broken which leaves room for bromine to be added to form dibromoethane.
Ethene undergoes addition reaction
Ethene reacts with water in presence of sulphuric acid and forms Ethyl alcohol.
The question is not very specific, so there is more than just one answer, but I'm assuming you are referring to a radical bromination of an alkane (ethane) versus an electrophilic bromination of an alkene (ethene).Br2 in the presence of a radical initiator (such as light or heat) will add to ethane to form 2-bromoethane as the major product in a radical mechanism. This goes through an initiation step (forming 2 bromine radicals), followed by propagation to the alkane (forming a secondary ethyl radical), followed by a termination step. The termination step leading to the product is one where another bromine radical joins with the ethyl radical.In the absence of light or heat, bromine cannot react with an alkane, but it can react as an electrophile with an alkene. In this type of reaction (electrophilic addition to an alkene), the ∏-bond (double bond) on ethene attacks a bromine atom (from Br2) and kicks out a bromide (Br-). The bromine that was just added forms two bonds (one on each carbon of the double bond), giving a three-membered C-Br-C ring called a bromonium ion (since the bromine atom now has a positive charge). The bromide that left before can now attack the backside of the bromonium ion, opening the 3-membered ring, and adding anti to form a dibromoalkane (1,2-dibromoethane in this example). This reaction is stereospecific because in the major product the bromine atoms will always add anti (to the opposite side) on the alkene.
You are trying to reduce ethane to ethene, I am guessing. That is a very hard reaction to do... probably you will have to do a free radical halogenation on ethane to form 1-chloroethane, followed by an E2 reaction with t-butoxide or some other bulky base to form ethene. Since ethane and ethene are both gases and cheaply available from petroleum cracking, this reaction really isn't worth doing.
forces between chemical reactions for example ethene reacting with hydrogen gas
Br2 + C2H4 → C2H4Br2 ORBr2 + CH2=CH2 → BrCH2CH2BrThe name of the reaction is pretty intuitive. Ethene's double bond is broken which leaves room for bromine to be added to form dibromoethane.
Ethene undergoes addition reaction
Such reactions are known as HYDRATION and are performed in presence of sulphuric acid.
As polyehtene is unsaturated(single bond) it does not react with bromine and there is no colour change.But bromine reacts with ethene and it becomes colourless.
1,2 dibromoethane and 1-bromo, 2-chloro ethane and 2-bromo ethanol
Bromine is an electrophile (electron deficient species) it attacks the Carbon doubble bond and accepts a pair of electrons. this is known as electrophillic addition. the equation is: C2H4 + Br2 - C2H4Br2 the product is 1,2 dibromoethane. this product is colourless.
because no free radicals are involved in the reaction process only carbo cations and Cl- are evolved which are ionic !!!
Ethene can react with Bromine water - turns colourless
The ethene doesnt change from orange to colourless as ethene is already colourless but the bromine water turns from orange to colourless.
It will turn colorless because bromine is an unsaturated compound and unsaturated compound have double bonds
The solution will turn the orange bromine water into a colourless solution
This is an addition reaction, as the double carbon-carbon bond in ethene breaks to accomodate the two chlorine atoms. Product is 1,2, dichloroethane