Usually when voltage increases current increases too, but when it happens that current decreases when voltage increase to minimize lose of power.
Total power = IV
Power loss = I * V(across wire) = I^2 R = (Power / V)^2 R
V = potential difference across the wire which is much smaller (you hope) than the total potential difference between the wire and ground.
So you lose less power using a very high voltage and a very low current for transmission and then transforming to the voltage you need at the point of delivery.
Power (P) in Electrical terms is Voltage (V) multiplied by Current (I)
i.e. P = V * I
Power is also rate of change of Energy with respect to time.
Accoding to Law of conservation of energy Energy can neither be created nor destroyed... meaning your power is constant. To satisfy this, if current increases voltage must decrease.
Not really practical case though, since to increase current you must decrease resistance (R). V = I * R. This will satisfy law of conservation of energy as well.
This question makes no sense as written. However, maybe it will help to know that for a given load if you increase voltage the current increases proportionally and if you decrease the voltage the current decreases proportionally. Ohm's Law says Voltage = Current x Resistance.
A: An impedance inversion is defined as voltage increases the current decreases. A tunnel diode has that detente
When the generator is loaded, flux per pole is reduced due to armature reaction.
The close the latitude is to 0, the hotter it is.
The electrical potential energy increases as the voltage is increased. It further excites the filament in the bulb more than a lessor voltage would. Using good old ohm's law (Voltage = Current x Resistance), a larger voltage applied to a bulb at the same resistance increases the current proportionally and larger currents has the effect to cause higher temps in conductors
Ohm's Law says that Voltage = Current x Resistance (Load). Therefore Current = Voltage / Resistance and as resistance decreases current increases and as resistance increases current decreases.
TRANSFORMER
Current increases if the voltage remains constant.
capacitors
Ohm's Law Voltage = Current x Resistance. So for a fixed voltage as R decreases then current increases proportionally.
Based on the simplest Electrical Equation V = I * R,(reads: voltage equals current multiplied by resistance)then, rearranged I = V / R .As resistance decreases, current flow proportionately increases
If the load current descrease, there is less voltage drop caused by the resistance of the wire, so the voltage is higher.
Ohm's law says the opposite.
If resistance increases and voltage stays the same, then current decreases. Ohm's Law: Current equals Voltage divided by Resistance.
P=VI If current (I) increases then P will increase proportionally. That is, assuming that voltage (V) remains constant. If voltage decreases and current increases or vice versa, proportionally then P will remain the same.
If the resistance is increased the current, which is inversely proportional, decreases and, the voltage drop increases.
Ohm's law states that "The current is directly proportional to the applied EMF (voltage) and inversely proportional to the resistance in the circuit." <<>> if resistor exists, resistance decreases according to ohm's law, current is directly proportional to voltage and current is inversely proportional to resistance it means as current increases, voltage increases. resistance increases, current decreases so as voltage if there is no resistor, there should be no resistance except internal resistance of voltmeter and ammeter