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it depends on what direction you take as the positive axis in a X,Y direction. if you say positive(X) is away from the earth then you would say gravity(g) is pulling the projectile the opposite direction from positive (X). if you say positive (X) is towards the center off the earth than you could say (g) is going with the (X) so g would end up positive.
in summary is depends on how you set up the X,Y axis compared to the problem you are solving.
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∙ 11y ago
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How do the horizontal components of a projectile motion vary from the vertical components?
Horizontal . . . acceleration is zero, speed is constant Vertical . . . acceleration is 'G' downward, speed constantly increases downward
In 0.5 seconds a projectile goes from 0 to 300 meter per second What is the acceleration of the projectile?
600 m/s2 ( About 61 G's ! )
In 0.5 seconds a projectile goes from 0 to 300 meters per second What is the acceleration of the projectile?
600 m/s2 ( About 61 G's ! )
What quantities remain constant in projectile motion?
All that I can think of are: 1.) Gravity 2.) Wind 2.A) wind speed 2.B) direction of wind 3.) Angle of trajectory 4.) Initial speed of projectile 5.) Material through which projectile travels (as in density) 6.) Mass of projectile 7.) Spin 7.A) speed of spin 7.B) axis/axes spining occurs on 8.) Shape of projectile 9.) Temperature of medium projectile is in 10.) Size of projectile (as in height, width, and depth) 11.) Weighting of projectile 12.) Obsturctions to projectile's path In a vaccuum, though, these are the variables: 1.) Speed of object 2.) Obstructions in path 3.) Gravity
Is there a difference between positive and negative g force?
Positive g-force is down. Negative g-force is up.
How do the horizontal components of a projectile motion vary from the vertical components?
Horizontal . . . acceleration is zero, speed is constant Vertical . . . acceleration is 'G' downward, speed constantly increases downward
If a projectile is shot in the air neglecting air resistance what is its vertical accelrration?
the vertical accelaration in case of a projectile is 'g'.
In 0.5 seconds a projectile goes from 0 to 300 meter per second What is the acceleration of the projectile?
600 m/s2 ( About 61 G's ! )
In 0.5 seconds a projectile goes from 0 to 300 meters per second What is the acceleration of the projectile?
600 m/s2 ( About 61 G's ! )
What conditions make G always negative?
G is always negative when H is negative and S is positive.
When you are going away from the earth then positive g or negative g is acting on your body?
Your motion relative to the Earth is of no consequences, instead calculate your bodies position relative to whatever is producing thrust. Note that without thrust, there are no "g's" to worry about.
What quantities remain constant in projectile motion?
All that I can think of are: 1.) Gravity 2.) Wind 2.A) wind speed 2.B) direction of wind 3.) Angle of trajectory 4.) Initial speed of projectile 5.) Material through which projectile travels (as in density) 6.) Mass of projectile 7.) Spin 7.A) speed of spin 7.B) axis/axes spining occurs on 8.) Shape of projectile 9.) Temperature of medium projectile is in 10.) Size of projectile (as in height, width, and depth) 11.) Weighting of projectile 12.) Obsturctions to projectile's path In a vaccuum, though, these are the variables: 1.) Speed of object 2.) Obstructions in path 3.) Gravity
Is N½ g 3H½ g æ 2NH¾ g entropy positive or negative?
negative
Will this entropy change by positive or negative n2 g 3h2 g 2nh3 g?
negative
What is the opposite of G?
negative G
What is the horizontal acceleration of a projectile as its position changes?
In the usual simple treatment of projectile motion, the horizontal component of the projectile's velocity is assumed to be constant, and is equal to the magnitude of the initial (launch) velocity multiplied by the cosine of the elevation angle at the time of launch.
What is maximum rang of projectile motion?
Suppose a projectile is fired from a gun, we know that "g" remains constant and as we use horizontal component of velocity in range sov0 also remains constant. Only sin2θ responsible for change in range. The range will be maximum if sin2θ has its maximum value that is 1.for maximum range:sin2θ = 12θ = sin-1 (1)θ = 90/2θ = 45 (degree)therefor if projectile is projected with the angle of 45(degree) its range will be maximum.
