answersLogoWhite

0

it depends on what direction you take as the positive axis in a X,Y direction. if you say positive(X) is away from the earth then you would say gravity(g) is pulling the projectile the opposite direction from positive (X). if you say positive (X) is towards the center off the earth than you could say (g) is going with the (X) so g would end up positive.

in summary is depends on how you set up the X,Y axis compared to the problem you are solving.

User Avatar

Wiki User

13y ago

What else can I help you with?

Continue Learning about Physics

How can one determine the maximum height reached in projectile motion?

To determine the maximum height reached in projectile motion, you can use the formula: textMaximum height left(fracv02 sin2(theta)2gright) where ( v0 ) is the initial velocity, ( theta ) is the launch angle, and ( g ) is the acceleration due to gravity. By plugging in these values, you can calculate the maximum height the projectile reaches.


What are the equations for projectile motion?

The equations for projectile motion are: Horizontal motion equation: x = v₀x * t Vertical motion equation: y = v₀y * t - 0.5 * g * t^2 Final velocity in the y-direction: v_yf = v₀y - g * t Where: x and y are the horizontal and vertical positions respectively v₀x and v₀y are the initial velocities in the x and y directions respectively g is the acceleration due to gravity t is the time elapsed


How do the horizontal components of a projectile motion vary from the vertical components?

In projectile motion, the horizontal component of motion is constant and does not change, while the vertical component is affected by gravity causing it to accelerate downwards. This results in a parabolic path of the projectile where the horizontal distance traveled is determined by the initial velocity and angle of projection, while the vertical distance is influenced by gravity.


What quantities remain constant in projectile motion?

All that I can think of are: 1.) Gravity 2.) Wind 2.A) wind speed 2.B) direction of wind 3.) Angle of trajectory 4.) Initial speed of projectile 5.) Material through which projectile travels (as in density) 6.) Mass of projectile 7.) Spin 7.A) speed of spin 7.B) axis/axes spining occurs on 8.) Shape of projectile 9.) Temperature of medium projectile is in 10.) Size of projectile (as in height, width, and depth) 11.) Weighting of projectile 12.) Obsturctions to projectile's path In a vaccuum, though, these are the variables: 1.) Speed of object 2.) Obstructions in path 3.) Gravity


How do you determine the range in a projectile motion?

Wind, elevation, trajectory, projectile weight, projectile configuration, barrel length, barrel rifling, friction or resistance in the barrel, force (charge) behind the projectile. There are other enviornental elements that can affect range as well.

Related Questions

What is the analytical equation for determining the trajectory of a projectile?

The analytical equation for determining the trajectory of a projectile is the projectile motion equation, which is given by: y xtan - (gx2) / (2v2cos2) where: y is the vertical position of the projectile x is the horizontal position of the projectile is the launch angle g is the acceleration due to gravity (approximately 9.81 m/s2) v is the initial velocity of the projectile


How can one determine the maximum height reached in projectile motion?

To determine the maximum height reached in projectile motion, you can use the formula: textMaximum height left(fracv02 sin2(theta)2gright) where ( v0 ) is the initial velocity, ( theta ) is the launch angle, and ( g ) is the acceleration due to gravity. By plugging in these values, you can calculate the maximum height the projectile reaches.


What are the equations for projectile motion?

The equations for projectile motion are: Horizontal motion equation: x = v₀x * t Vertical motion equation: y = v₀y * t - 0.5 * g * t^2 Final velocity in the y-direction: v_yf = v₀y - g * t Where: x and y are the horizontal and vertical positions respectively v₀x and v₀y are the initial velocities in the x and y directions respectively g is the acceleration due to gravity t is the time elapsed


How do the horizontal components of a projectile motion vary from the vertical components?

In projectile motion, the horizontal component of motion is constant and does not change, while the vertical component is affected by gravity causing it to accelerate downwards. This results in a parabolic path of the projectile where the horizontal distance traveled is determined by the initial velocity and angle of projection, while the vertical distance is influenced by gravity.


If a projectile is shot in the air neglecting air resistance what is its vertical accelrration?

the vertical accelaration in case of a projectile is 'g'.


What quantities remain constant in projectile motion?

All that I can think of are: 1.) Gravity 2.) Wind 2.A) wind speed 2.B) direction of wind 3.) Angle of trajectory 4.) Initial speed of projectile 5.) Material through which projectile travels (as in density) 6.) Mass of projectile 7.) Spin 7.A) speed of spin 7.B) axis/axes spining occurs on 8.) Shape of projectile 9.) Temperature of medium projectile is in 10.) Size of projectile (as in height, width, and depth) 11.) Weighting of projectile 12.) Obsturctions to projectile's path In a vaccuum, though, these are the variables: 1.) Speed of object 2.) Obstructions in path 3.) Gravity


How do you determine the range in a projectile motion?

Wind, elevation, trajectory, projectile weight, projectile configuration, barrel length, barrel rifling, friction or resistance in the barrel, force (charge) behind the projectile. There are other enviornental elements that can affect range as well.


What is the range of a projectile launched from a height of 60m with maximum height 44.1m which reaches 76 m from the base?

Suppose a ball falls from rest from height h, then by equation of motion: h=1/2*g*t2 . and for horizontal motion, x=vx*t. put value of t in first equation: h=1/2*g*x2/v2, or x=(h*2*v2/g)1/2. or x=k*h1/2, so x1/h11/2=x2/h21/2; put the values, x1=601/2*76/44.11/2; Work with calculator now......


What conditions make G always negative?

G is always negative when H is negative and S is positive.


When you are going away from the earth then positive g or negative g is acting on your body?

Your motion relative to the Earth is of no consequences, instead calculate your bodies position relative to whatever is producing thrust. Note that without thrust, there are no "g's" to worry about.


Will this entropy change by positive or negative n2 g 3h2 g 2nh3 g?

negative


What is the opposite of G?

negative G