Yes, most probably Van der Waals interactions
The opposite sequence, so the two strands can bind together to form a dimer.
A dimer is defined as two identical molecules sharing a covalent bond. maltose is two C6H12O6 molecules that are combined via a covalent bond, making it a true Dimer. hope that helped :)
D dimer is a protein fragment that is found in the blood after someone has had a blood clot. Fibrinolysis breaks down the clot, leaving D dimer in the blood. The D dimer blood test is usually performed when doctors suspect that a patient has a pulmonary embolism (blood clot in the lung) or deep venous thrombosis. While a negative D dimer blood test usually means that a blood clot is not present, a positive D dimer blood test does not necessarily indicate a blood clot or deep venous thrombosis
The question is too vague to definitively answer, but the word you're looking for might be "disaccharide".
The dimer C02(CO)8 is not soluble in water.
Julius Dimer died in 1945.
Julius Dimer was born in 1871.
Benzene is a non polar solvent with low dielectric constant, whereas water is a polar solvent with high dielectric constant. So water can reduce the interaction between benzoic acid molecules there by preventing them from dimerizing, which cannot be done by benzene
Two monomers are joined to make a dimer.
The opposite sequence, so the two strands can bind together to form a dimer.
IgA
The formula of the usual elemental oxygen molecule is O2, showing two atoms per molecule. (This answer is coded in the phrase "dimer structure" itself, because "dimer" means "two units".)
Sucrose, lactose and etc.
normal
A normal D-dimer test result means that the patient who has taken the test does not have an acute disease or condition causing abnormal clotting and breakdown. D-dimer is a substance released upon breaking down of blood clots.
stupid question..!
A dimer is defined as two identical molecules sharing a covalent bond. maltose is two C6H12O6 molecules that are combined via a covalent bond, making it a true Dimer. hope that helped :)