Yes.
60 x 45 Joules.
A 3 watt led light is not the same as a 45 watt bulb. A led light is a lot brighter.
The base of the bulb obviously determines where it can fit and for most home fixture cases determines the voltage (Unfortunately there are many speciality bulbs where the base can fit different voltage situations and you have to be more careful). Light fixtures are rated for a maximum wattage. Bulbs have both a wattage and voltage rating. So if the halogen fits the base, is the same voltage and the fixture is rated for 45 watts or better, then you are good to go.
To do any replacements of different bulbs you have to consider what the new current will be and if the wire size and fuse will be able to take the new current (amps). Use this formula, W = A x V or A = W/V.
Work is how much energy is transferred, measured in Joules. Power is how fast or slow the work is transfered, measured in Joules per second. One joule per second is called one Watt of power. This meams a 60 Watt light bulb converts 60 joules of electrical energy into roughly 15 joules of light and 45 Joules of heat every second its switched on for.
Yes, eventually. The components of the light itself are only designed to handle the heat of the 45 watt bulb. The extra heat from the 60 watt bulb would eventually damage parts of the light, including the wires.
A kilowatt hour (kWh) is used to measure energy consumption. It is defined as 'the energy consumed, over a period of one hour, at a rate of one kilowatt'.To determine how many kilowatt hours are consumed, you must multiply the power of the lamp, expressed in kilowatts, by the length of time it is in use, expressed in hours.So, a 45-W lamp will use: (45/1000) x 1 = 0.045 kWh per hour of use.
A 100 watt 220 volt light bulb (or anything consuming 100 watts on 220 volts) draws 100/220, or .45 Amps. It will also have about 220²/100, or 484 ohms resistance. A 60 watt 220 volt light bulb (or anything consuming 60 watts on 220 volts) draws 60/220, or .27 Amps. It will also have about 220²/60, or 807 ohms resistance.
There are two license plate bulbs on the 2000 Sonata. They are housed individually. The housing itself releases easily enough. Grip the housing with your thumb and fore finger, thumb on the right hand side of the housing, squeeze the clip under the thumb and pull down the housing. It does not come out very far. The cables are taped to the bumber of the car, you may need to reach up behind the bumper and find the tape and cut it, taking care not to cut the wires. Once you have released the cables, the housing should come out sufficiently for you to grip the bulb connecter. Holding it, turn the housing clockwise about 45 degrees and pull it off the bulb connector. It is all very stiff and difficlut to access, but it is possible, I have replaced one and it does work.
A 45-watt electric fan means that it consumes 45 watts of electrical power to operate. This power rating indicates how much electricity the fan uses while running.
60 and 100 watt in series then the 60 watt will have the biggest voltagedrop.In parallel they are the same.Using a voltage of 120 volts, the 60 watt lamp would have 75 volts across it and the 100 watt lamp would have 45 volts across it in a series circuit, bringing the total to 120 volts.
45