Yes, cinnamaldehyde can react with Fehling's reagent to form an orange-red precipitate of copper(I) oxide. This is because aldehydes are capable of reducing the copper(II) ions present in the Fehling's reagent to form the insoluble copper(I) oxide.
No, starch does not reduce Fehling's solution. Starch is a polysaccharide composed of glucose molecules linked together, whereas Fehling's solution is a complex of copper sulfate, sodium hydroxide, and potassium sodium tartrate used to test for the presence of reducing sugars. Starch is not a reducing sugar and therefore will not react with Fehling's solution.
This oil is a mixture, not a compound; the principal component is cinnamaldehyde.
Starch does not give a positive result in the Fehling test because starch is a polysaccharide made up of glucose units linked together in a way that does not allow the formation of free aldehyde or ketone groups required for the Fehling test to detect reducing sugars. Since starch is a larger molecule, it does not react with the Fehling reagent designed to detect the presence of smaller reducing sugars like glucose and fructose.
fehling a is copper sulphate and fehling b is alkaline solution of sodium pottasium tartarate
Yes, it will. Maltose has a free aldehyde group in its linear form, then this aldehyde reduces Cu2+ forming the cuprous oxide (CuO) which is a reddish precipitate. This is the Fehling reaction.
Yes, cinnamaldehyde can react with bromine to form dibromocinnamaldehyde. This reaction involves the addition of bromine across the carbon-carbon double bond in the cinnamaldehyde molecule.
Fehling's test is used to differentiate between aldehyde and ketones group. An aldehyde group will react with Fehling's reagent to give cuprous oxide resulting in a red precipitate. A Ketone group will not react with Fehling's reagent.
No, formic acid does not react in the Fehling's test. The Fehling's test is specifically used to test for the presence of reducing sugars. Formic acid is a carboxylic acid and does not possess a reducing sugar functionality.
No, starch does not reduce Fehling's solution. Starch is a polysaccharide composed of glucose molecules linked together, whereas Fehling's solution is a complex of copper sulfate, sodium hydroxide, and potassium sodium tartrate used to test for the presence of reducing sugars. Starch is not a reducing sugar and therefore will not react with Fehling's solution.
The compound is likely a ketone. Ketones do not react with Fehling's or Tollens' reagent to form precipitates, unlike aldehydes which would undergo redox reactions resulting in a visible change.
This oil is a mixture, not a compound; the principal component is cinnamaldehyde.
Cinnamaldehyde is an aldehyde. Its structure contains an aldehyde functional group (-CHO) attached to a benzene ring.
Starch does not give a positive result in the Fehling test because starch is a polysaccharide made up of glucose units linked together in a way that does not allow the formation of free aldehyde or ketone groups required for the Fehling test to detect reducing sugars. Since starch is a larger molecule, it does not react with the Fehling reagent designed to detect the presence of smaller reducing sugars like glucose and fructose.
melting point of cinnamaldehyde semicarbazone
Alexander Fehling is 184 cm.
Ruth Fehling has written: '\\'
fehling a is copper sulphate and fehling b is alkaline solution of sodium pottasium tartarate