fehling a is copper sulphate and fehling b is alkaline solution of sodium pottasium tartarate
Fehling A and B Benedict solution
When Fehling A & B are mixed in equal quantities... Fehlings Reagent is formed which is DEEP BLUE in colour Hope that answers your question! :)
fehling's solution is dark blue at room temperature "Fehling's solution" is prepared by dissolving separately 34'639 grammes of copper sulphate, 173 grammes of Rochelle salt, and 71 grammes of caustic soda in water, mixing and making up to l000 ccs.; 10 ccs. of this solution is completely reduced by o 05 grammes of hexose
The function of Fehling's testing is to detect aldehydes. There are 2 solutions necessary. The chemical composition is 7 g CuSO4.5H2O dissolved in distilled water containing 2 drops of dilute sulfuric acid and 35g of potassium tartrate and 12g of NaOH in 100 ml of distilled water.
When the two Fehling Solutions A and B are mixed, a deep blue solution containing a complex cupric ion is formed. On interaction with reducing compounds such as aldehydes or sugars, the copper is reduced to the univalent stage, and a red, yellow, or yellowish green precipitate is formed.
Fehling's solution is made up of two separate solutions: Fehling's A (copper sulfate solution) and Fehling's B (potassium sodium tartrate and sodium hydroxide solution). When combined in equal parts, these solutions are used to test for the presence of reducing sugars like glucose in a chemical sample.
Fehling solution "A" is copper sulphate solution and Fehling solution "B" is a solution of sodium potassium tartrate and NaOH.
Fehling's A and Fehling's B are used together in the Fehling's test to detect the presence of reducing sugars, such as glucose. Fehling's A is a copper(II) sulfate solution, while Fehling's B is a complex solution of potassium sodium tartrate and sodium hydroxide. They work together to oxidize the sugar, causing a color change that indicates the presence of a reducing sugar.
The Fehling A solution contain copper sulfate.The Fehling B solution contain sodium potassium tartrate and sodium hydroxide.
Fehling A and B Benedict solution
When Fehling A & B are mixed in equal quantities... Fehlings Reagent is formed which is DEEP BLUE in colour Hope that answers your question! :)
fehling's solution is dark blue at room temperature "Fehling's solution" is prepared by dissolving separately 34'639 grammes of copper sulphate, 173 grammes of Rochelle salt, and 71 grammes of caustic soda in water, mixing and making up to l000 ccs.; 10 ccs. of this solution is completely reduced by o 05 grammes of hexose
The function of Fehling's testing is to detect aldehydes. There are 2 solutions necessary. The chemical composition is 7 g CuSO4.5H2O dissolved in distilled water containing 2 drops of dilute sulfuric acid and 35g of potassium tartrate and 12g of NaOH in 100 ml of distilled water.
Benedict's solution is used to test for the presence of reducing sugars, such as glucose, in a sample. It is more sensitive than Fehling's solution, which is also used to test for reducing sugars but is less commonly used due to its complexity and need for separate solutions (Fehling's A and B) to be mixed in a specific ratio before testing. Benedict's solution is a single solution that is easier to use.
When the two Fehling Solutions A and B are mixed, a deep blue solution containing a complex cupric ion is formed. On interaction with reducing compounds such as aldehydes or sugars, the copper is reduced to the univalent stage, and a red, yellow, or yellowish green precipitate is formed.
Both Fehling's and Benedict's tests are used to detect the presence of reducing sugars in a solution, such as glucose. The key difference lies in the composition of the reagents: Fehling's solution is made up of separate A and B components that need to be mixed before testing, while Benedict's solution is a single solution containing the necessary components. Additionally, Fehling's solution is more sensitive than Benedict's solution.
Sodium hydroxide is added to Fehling's solution B to provide the alkaline conditions necessary for the oxidation of reducing sugars. This allows the copper (II) ions in the solution to be reduced by the aldehyde or ketone functional groups in the reducing sugar, resulting in the formation of a red precipitate of copper (I) oxide.