It has a greater affect on the person at sea level, but you would need extremely precise scientific instruments to detect it.
the moons gravitational pull
One G is the gravitational force the earths gravity has. Any other force such as that provided by an airplane in a steep turn can be measured in multiples of that "one G".
When you get out of earths gravitational pull, you aren't rotating around it like the moon. You are free to float into space.
Mainly because we are in "free fall" around the Sun. In such situations, gravity won't be noticed. Also, Earth's gravitational force is much stronger, anyway, because Earth is much closer.
Less than one tenth (1/10) of the earths gravitational pull.
yes
it is 10N/Kg
WIEGHT
9.8 N/kg
Standing at surface radius its = 9.82 (m/s)/sbut double the radius and the acceleration drops to 9.82 / ((2 / 1)2) = 2.455 (m/s)/s
ahhh now.... When a spacecraft leaves earths atmoshere it does not leave earths gravitational pull! the moon itself is in earths gravitational pull. which is what stops the moon from floating away so as far as i can imagine if you put a space craft on the moon you have not left earths gravitational pull or the E.G.P
The gravitational field is stronger the closer you are to the Earth, so a person standing 100m up will experience a stronger tug than a person standing 200m up.