According to all the laws of optics, no, but there's more to it. If the mirror is of
relatively low quality, especially if the reflecting coating is on the back and the
light has to pass through the glass twice when it bounces, then the focal length
may be slightly different for different wavelengths. The result is that you see
thin borders of color around objects when you look at them in the mirror. This
is considered a cheapo mirror with a severe fault. It might be OK to shave with,
but it would never be used in an optical system like a telescope.
Velocity increases when sound waves travel from gas medium to solid medium. As velocity = frequency * wave length and the frequency does not change, v is directly proportional to the wave length... Hence the wavelength increases.
No. The length of a sound wave is it's frequency. Volume will increase the wave's AMPLITUDE.
The wavelength of the x-ray is shorter.
If the sides of a cell doubles, this volume will increase by 8 times. Here is an explanation: Say you have a cell with the side dimension equal to n. The volume of the cube is n3 Double the side lenght to 2n The volume is now (2n)(2n)(2n) = 8n3
Speed = distance / time [m /s]likewise:Speed of wave = wavelength x frequency [m /s]Since sound waves travel at a fixed speed through a medium* a drop in frequency must cause a corresponding increase in wavelength*Not always true. In water of example, lower frequency waves travel faster than higher frequency waves. When this happens the waves are said to be travelling through a dispersive medium.
Speed is (Length/Time). Wavelength is (Length), and Frequency is (1/Time).Speed = (Wavelength)*(Frequency). With a constant speed, Wavelength and Frequency are inversely proportional to each other. So if one increases, the other decreases.
With a water wave, an increase in the length of the wavelength will result in a decrease in the frequency of the wave. We could say that there is an inverse relationship between the frequency and the wavelength. As one increases, the other decreases, and as one decreases, the other increases.
For electromagnetic radiation,c = speed of light = 3.0 x 108 m/s = frequency x wavelengthAs the frequency of light waves increase, the wavelength decreases. For electromagnetic radiation, the wavelength times the frequency equals the speed of light, c, which is 3.0 x 108 m/s. So, if the frequency increases, the wavelength will decrease, and if the wavelength increases, the frequency decreases.
No. the wave length decreases as the frequency of an energy wave increases and vise versa. We acyually are learning thatin my 8th grade science class.
dispersion increases and wavelength decreases
the wave length will increase
Frequency is inversely proportional to the wave length, thus saying the shorter the wave length the higher the frequency and vice versa.The frequency is the number of waves within a time period. As the frequency within that time period increases, the number of waves increases, therefore the width of each wave (wavelength) within that time period has to decrease. Therefore:As the wave length increases, the frequency decreasesAs the wave length decreases, the frequency increases
Wavelength shortens as frequendcy increases.
Velocity increases when sound waves travel from gas medium to solid medium. As velocity = frequency * wave length and the frequency does not change, v is directly proportional to the wave length... Hence the wavelength increases.
it would increase
Increases with length and connections.
Longer wavelength less energy and shorter wavelength equals more energy. This is because velocity (speed)=frequency x wavelength. And te velocity of all EM waves is the speed of light. we know the expression- frequency=speed of light(c)/wavelength Energy is given by- E=h*frequency=h*c/wavelength {h=Planck's constant} so,energy is directly proportional to frequency and inversly proportional to wavelength...that is energy increases with increase in frequency and decreases with increase in wavelength. example:-red color has more wavelength and hence has less energy.