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Depends what you mean when you say "burn out". That's actually a pretty imprecise term.

Usually, when we talk about a single passive component "burning out", we mean that some part
of it became so hot that the conducting path melted at some point and became "open" at that point.
When that happens, the open gap has a very high resistance, and current can't flow across it.

So I guess we'd have to say 'no'; when current can't flow through the resistor, then there is
no current flow through the resistor.

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Q: Will there be a current flow if the resistor burn out which is connected in series?
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