Depends what you mean when you say "burn out". That's actually a pretty imprecise term.
Usually, when we talk about a single passive component "burning out", we mean that some part
of it became so hot that the conducting path melted at some point and became "open" at that point.
When that happens, the open gap has a very high resistance, and current can't flow across it.
So I guess we'd have to say 'no'; when current can't flow through the resistor, then there is
no current flow through the resistor.
Resistors are rated in wattage so the lowest wattage rating will be the wattage of the series circuit. It will be able to handle that power any more and the lowest wattage resistor could be damaged and fail.Another AnswerWhen two or more resistors are connected in series, the resistor with the lowest resistance will operate at the highest power. If the power developed by a resistor exceeds its rated power, then the resistor may burn out.
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
cause its bad,replace with higher wattage rating.too much current !!
The breaker panel. Breakers are placed in series with all outlets.
Connecting an ammeter in parallel subjects that ammeter to the full supply voltage. The shunt resistor is not designed to sustain that value of voltage and will burn out. Also, the clue is in the word 'shunt' (which means 'in parallel') which means that the coil will also burn out!
An LED usually has a resistor connected in series with it because an LED (light emitting diode) is not linear in current to voltage (like a resistor) and has to be operated within specified current and voltage conditions. In most circuits the supply voltage is higher than the forward voltage of the LED so the LED would burn up from too much current without a current limiting resistor in series. The resistor sets the voltage and current to a good operating point (voltage and current) for the LED by dropping some voltage across it. The operating point varies depending on the size, type and manufacturer of an LED so the LED's data is used to select the right resistor size for a given voltage source.
Resistors are rated in wattage so the lowest wattage rating will be the wattage of the series circuit. It will be able to handle that power any more and the lowest wattage resistor could be damaged and fail.Another AnswerWhen two or more resistors are connected in series, the resistor with the lowest resistance will operate at the highest power. If the power developed by a resistor exceeds its rated power, then the resistor may burn out.
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
cause its bad,replace with higher wattage rating.too much current !!
Depends on the current. Put a resistor in-line with the current, then measure the voltage across the resistor. V=RI. So, divide the measured voltage by resistor value. Be careful with the size of the resistor, as Power dissipated in a resistor is R*I^2 or V^2/2. So, a 1-Amp current into a 1 Ohm resistor will result in a 1Watt power dissipated in the resistor. If it's too small, it'll burn. Also, notice that if you do that, you haven't measured the current in the original circuit. You've measured the current when an extra resistor is installed in the original circuit, and that's different.
It will if the batteries are connected in series. If they are connected in parallel, the lamp will burn longer, but not brighter.
It will burn due excess current .
The breaker panel. Breakers are placed in series with all outlets.
Most often a resistor fails because it is unable to properly dissipate the heat generated by the current flow. A resistor rated for more power (higher wattage) may resolve the problem.
Connecting an ammeter in parallel subjects that ammeter to the full supply voltage. The shunt resistor is not designed to sustain that value of voltage and will burn out. Also, the clue is in the word 'shunt' (which means 'in parallel') which means that the coil will also burn out!
In an electric circuit, ratio of current and voltage is constant which is known as the resistance of the circuit. If voltage or current is to be changed the resistance has to be changed. You cannot keep an invariable resistance in the circuit and increase current while keeping voltage as constant.Hence to vary the voltage or current in a circuit different equipments like rheostat,potentiometer are used.
If dry cells are connected in parallel, they will supply more current to the bulb, which will cause it to glow for a longer period of time, but at the same brightness as if only a single cell were used. When the cells are connected in series, the voltage is increased, which will cause the bulb to burn more brightly. If the voltage is increased past the safe point for the bulb, its life will be shortened and it may burn out rapidly. In series, the voltages add. In parallel, you essentially have a larger cell of the same type (cell as in battery of one).