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When resistors are connected in series then what happens to the watt?
Wiki User
∙ 9y ago
Resistors are rated in wattage so the lowest wattage rating will be the wattage of the series circuit. It will be able to handle that power any more and the lowest wattage resistor could be damaged and fail.
Another Answer
When two or more resistors are connected in series, the resistor with the lowest resistance will operate at the highest power. If the power developed by a resistor exceeds its rated power, then the resistor may burn out.
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∙ 9y ago
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What would the current draw be if there was six ten ohm resistors connected in series across a 120 volts?
The total current in a circuit consisting of six operating 100 watt lamps connected in parallel to a 120 volt source is 5 amperes. Since power is volts times amps, take 600 watts (100 times 6) and divide by 120 volts to get 5 amps.
How is a watt meter connected?
There are two coils in watt meter namely current coil & potential coil.the two ends of current coil are 'M' & 'L' and they should connect in series with instrument. and the two ends of p.c. is 'c' which is connected to 'L'. and another is at the other end of instrument.There are two coils in watt meter namely current coil & potential coil.the two ends of current coil are 'M' & 'L' and they should connect in series with instrument. and the two ends of p.c. is 'c' which is connected to 'L'. and another is at the other end of instrument.There are two coils in watt meter namely current coil & potential coil.the two ends of current coil are 'M' & 'L' and they should connect in series with instrument. and the two ends of p.c. is 'c' which is connected to 'L'. and another is at the other end of instrument.
A 100 ohm 1 watt resistor and 800 ohm 2 watt resistor are connected in seriesmaximum dc output voltage that can be applie continuously to series circuit without exceeding power limit of resistor?
If a 100 ohm 1 watt resistor and an 800 ohm 2 watt resistor are connected in series, the maximum DC voltage that can be applied without exceeding the power limit of both resistors is 45 volts. Start with power rule and ohm's law... P = IE E = IR so P = I2R solve for current I2 = P/R I = (P/R)0.5 determine current at max power for each resistor R1 = 100, R2 = 800 I1 = (1/100)0.5 = 0.1 amperes I2 = (2/800)0.5 = 0.05 amperes The limiting resistor is R2, so calculate voltage of both at current flow of I2 V1+2 = (0.05)(900) = 45 volts
What does a 220 resistor do?
The watt rating of a resistor is directly proportional to their physical size. Resistors generate heat just like any resistive load. Small resistors usually are rated at 1/4 watts, larger resistors about 1/4 in diameter have a 2 watt heat dissipation capacity. Ceramic wire wound resistors are wound on a tube form so that there is more surface area and cooling air can pass up through the tube. These types of resistors can dissipate up to 50 watts of unwanted heat. <<>> None. Resistors do not have watts. Watts, ohms, amps, volts, farads... are all ways to measure electrical properties, and while there are interrelations, watts refer to the total amount of energy that a device consumes or produces.
What is function of pressure coil in a watt meter?
A 'pressure coil' is an archaic term for a 'voltage coil' (UK terminology) or 'potential coil' (US terminology), as opposed to the 'current coil' in a wattmeter. This coil is connected in parallel with the supply, while the current coil is connected in series with the load.
If you are only given 1 kilo ohms resistors with 0.5 watt power rating how can you construct a resistive load of 1 kilo ohms with 1 watt power rating?
Well...you can't. Not a load with an exact 1 watt power rating. But if you can live with a 2-watt power rating (in a circuit that would be yes--it's called derating and you do it for added life, or because you've already got the parts) you'd connect two resistors in series and set that aside, connect two more resistors in series, then connect the two series networks in parallel. Each series network is rated at 2 kilohms; paralleling the two networks brings you back down to 1 kilohm.
What is the max voltage for 3 50ohmn resisters?
It depends on the power rating of the resistors. The total power of a series or parallel combination of resistors is the sum of the power rating of each. Here is one possible answer that assumes the resistors are rated at 1/4 watt and are connected in series. Power = Current ^ 2 x Resistance. The ^ means squared. Current = square root (Power / Resistance) Current = square root (0.25 / 50) = 0.0707 amps The total power of the three resistors in series is 0.25 x 3 = 0.75 watts Current = square root (0.75 / 150) = 0.0707 amps <-- Notice you get the same current as before. This must be true because the current flowing through a series circuit is the same in each component. Since Voltage = Current x Resistance Voltage = 0.0707 x 50 = 3.54 volts across one of the resistors OR Voltage = 0.0707 x 150 = 10.61 volts across the series combination. Here's another way to calculate the answer. Voltage = square root of (Power x Resistance) Voltage = square root (0.25 x 50) Voltage = 3.54 volts This is the maximum voltage across one of the resistors. If the three resistors are connected in series, the total resistance would be 150 ohms and the maximum voltage across the series combination would be 3.54 x 3 = 10.61 volts. If the resistors are connected in parallel, the equivalent resistance is 16.67 ohms. Since the voltage across parallel resistors is the same, the maximum voltage for three 1/4 watt resistors would be square root (0.75 x 16.67) = 3.54 volts. This is the same answer calculated for the resistors in series. The maximum current through each resistor is V / R = 3.54 / 50 = 0.0707 amps or the same current as the series combination. However, in this case, the total current flowing through the parallel combination is 0.0707 x 3 = 0.2121 amps and Power = I ^ 2 x R = .2121 ^ 2 x 16.67 = 0.75W. This proves that the powers add no matter if the resistors are in series or parallel. If the resistors are rated at 1/2 watt the maximum voltage across one resistor is 5 V and the maximum across the series combination is 15 V. The maximum current is 0.1 A.
For bulbs connected in series the high watt bulb has high resistance?
No, the highest wattage bulb will have the lowest resistance.
What would the current draw be if there was six ten ohm resistors connected in series across a 120 volts?
The total current in a circuit consisting of six operating 100 watt lamps connected in parallel to a 120 volt source is 5 amperes. Since power is volts times amps, take 600 watts (100 times 6) and divide by 120 volts to get 5 amps.
What happens of watt when two resistor is connected in series or parallel connection?
In case of parallel combination watt increases with respect to series combination. Let, V=12v,Ra=5 Ohm, Rb=3 Ohm then Rse=Ra+Rb=8 Ohm Rpa=Ra.Rb/(Ra+Rb)=1.875 Ohm Now, P=IV or V^2/R then Pse=12^2/8=18W Ppa=12^2/1.875=76.8W So from here we can easily understand that why watt increases in parallel combination w.r.t series combination.
How is a watt meter connected?
There are two coils in watt meter namely current coil & potential coil.the two ends of current coil are 'M' & 'L' and they should connect in series with instrument. and the two ends of p.c. is 'c' which is connected to 'L'. and another is at the other end of instrument.There are two coils in watt meter namely current coil & potential coil.the two ends of current coil are 'M' & 'L' and they should connect in series with instrument. and the two ends of p.c. is 'c' which is connected to 'L'. and another is at the other end of instrument.There are two coils in watt meter namely current coil & potential coil.the two ends of current coil are 'M' & 'L' and they should connect in series with instrument. and the two ends of p.c. is 'c' which is connected to 'L'. and another is at the other end of instrument.
How many 60 Watt light bulbs can be lit with a 300 watt generator?
3 bulb can be connected..............................
How do design a high voltage digital voltmeter on DC?
you need to know the input impedance of the voltmeter it will say something like 10000 ohms/volt if the digital meter is 1Volt full scale you can make it into a 10V meter by putting it in series with a 100K ohm resistor you can make it into a 10000v meter by putting it in series with a 100MegOhm resistor the being said resistors in the 100megohm size are hard to find since tubes went away. if you look at specs 1/8 watt resistors may not be able to take more than 100v without arc over 1/4 watt will go perhaps 200v so you can make 100Meg ohm resistor with 50 each 2 meg ohm resistors in series to make sure you dont exceed the voltage rating now check power rating 10000 ohms / volt is 10 micro amps full scale 10,000 volts at 10 microamps is 1/10th watt fine for 1/4 watt resistors since we actually constructed a 12 watt resistor connect your resistors end to end and put them inside a clear plastic tube so you can observe any arc overs to make a 100,000V meter just use 500 2 meg resistors the second anode on a big crt color tv uses about 30,000v the is positive to ground the older microwave ovens were 10,000v newer ones are 2000v can make better magnets now i guess the plate of the tube is grounded so source will be negative be very careful with high voltage your first mistake is usually your last 10 milliamps can kill. the microwave will give you an amp or so.
How many 12 volt batteries does it take to power a 3000 watt invertet for 24 hours?
You need 3000 x 24 watt-hours or 72,000 watt-hours. A typical car battery has a capacity of 50 Ah or 600 watt-hours, so you would need 120 car batteries, connected in the right combination of series and parallel to give the right voltage for the inverter.
A 100 ohm 1 watt resistor and 800 ohm 2 watt resistor are connected in seriesmaximum dc output voltage that can be applie continuously to series circuit without exceeding power limit of resistor?
If a 100 ohm 1 watt resistor and an 800 ohm 2 watt resistor are connected in series, the maximum DC voltage that can be applied without exceeding the power limit of both resistors is 45 volts. Start with power rule and ohm's law... P = IE E = IR so P = I2R solve for current I2 = P/R I = (P/R)0.5 determine current at max power for each resistor R1 = 100, R2 = 800 I1 = (1/100)0.5 = 0.1 amperes I2 = (2/800)0.5 = 0.05 amperes The limiting resistor is R2, so calculate voltage of both at current flow of I2 V1+2 = (0.05)(900) = 45 volts
What does a 220 resistor do?
The watt rating of a resistor is directly proportional to their physical size. Resistors generate heat just like any resistive load. Small resistors usually are rated at 1/4 watts, larger resistors about 1/4 in diameter have a 2 watt heat dissipation capacity. Ceramic wire wound resistors are wound on a tube form so that there is more surface area and cooling air can pass up through the tube. These types of resistors can dissipate up to 50 watts of unwanted heat. <<>> None. Resistors do not have watts. Watts, ohms, amps, volts, farads... are all ways to measure electrical properties, and while there are interrelations, watts refer to the total amount of energy that a device consumes or produces.
Which light will glow better if 3060 and 100 watt bulb are connected in series?
The lamp with the lowest (30 W) power rating will have the highest resistance, and be subject to the highest voltage drop and, will, therefore, be the brightest.
