Yes, transformer losses will be the same for any linear load with the same VA. However, if the load is nonlinear, such as a rectifier, the load waveform will be distorted and the losses will be higher than with an undistorted sinusoidal load current of the same VA
Yes because the VA are determined by the voltage and the current, and these are what produce heating in the transformer. The voltage produces heating by eddy currents in the iron core, while the current produces heating in the resistance of the primary and secondary windings. That is why Transformers are rated in VA, kVA, etc and not watts or kilowatts.
The rating of the machine (kva or kw) depends upon the power factor, since the load power factor to which the transformer is supplying power is not known, it may be capacitive, inductive, or resistive that is why its rating is in kva not in kw.
a transformer require AC to function as desired it transform the AC to different levels. DC on a transformer can only see the actual primary or secondary resistance if the source is not limited in current it will burn the transformer by excessive heating since it will see only wire resistance. Answer 2 the application of an AC voltage, V on one winding of the transformer produces alternating flux that links the entire core of the transformer. The changing flux induces an emf, E that opposes the main voltage. the current through the winding in this case is {(V-E)/R}; R= winding resistance in case of application of DC, since there is no changing flux, there is no induced emf and hence the current will be V/R since the resistance of the winding is very small, the current is very high and this can burn away the windings. hence DC is not used.
Transformer cores are chosen to limit eddy currents, which cause heating and losses in the core. Very thin laminations minimize this overhead cost of running a transformer by reducing losses associated with eddy currents.
As per transformer equation,E=4.44 * freq * flux * Turns.So E/ freq =Flux. So when a transformer is designed for 60Hz ,it CANNOT be operated at 50Hz and if operated may create heating effects and core saturation etc. Because E/60< E/50. However the converse condition is true i.e. a 50 HZ transformer can be used for 60Hz application Because E/50>E/60
Current overload from whatever circuit draws current from the transformer? Proper fusing of its supply might protect a transformer from this cause. Or it could have developed a shorted turn fault because the insulation on a winding got old and perished? Or maybe the transformer got damaged if the appliance it is mounted in was dropped?
Yes because the transformer heating (power losses) depend on the load current and the load voltage. It can be assumed that the voltage stays more or less constant, therefore the iron loss is also constant. The copper loss depends on the square of the load current. So it is the VA of the load that determines the power loss and any heating.
The rating of the machine (kva or kw) depends upon the power factor, since the load power factor to which the transformer is supplying power is not known, it may be capacitive, inductive, or resistive that is why its rating is in kva not in kw.
Knowing the power rating of a transformer will help an operator use the transformer within its design limitations with regard to heating of the windings and their insulation.
Power factor is the cosine of an AC circuit's phase angle, where the expression phase angle is the angle by which a load current lags or leads the supply voltage.Lagging phase angles and power factors occur in resistive-inductive circuits. Leading phase angles and power factors occur in resistive-capacitive circuits.Most industrial and commercial loads are combinations of heating (resistive) loads and motor (inductive) loads -in other words, resistive-inductive loads. Accordingly, lagging power factors tend to be more common than leading power factors.
he made pizza with a heating iron and a transformer......Bumblebee
usually 40 va
It will work ok. The iron's heating element is predominately resistive in order to produce heat. If the heating element is coiled, it will have a small inductive reactance which acts similar to a resistance to current flow but does not contribute to heating. At a higher a.c. frequency (60 Hz instead of 50 Hz) it will have a slightly higher inductive reactance and, therefore, a slight reduction in heat production.
it won't get as hot
If the frequency drops, then overall impedence reduces and hence the current tend to increase, leading to over heating and ultimately may damage the transformer
Alternating Current for highly inductive load i.e. motors...whereas AC21 is for resistive load....i.e. heating elements. this is what you called utilization category...
The output of a transformer is NOT dependent on laminations. It is dependent upon the turns ratio and input voltage and current. The core of transformers is often laminated to minimize eddy currents - currents that don't flow in the desired direction, and cause extra heating in the transformer (minimizing lowers the amount of losses in the transformer).
A transformer gets hot if it is run at excessive voltage or excessive current. Either of those two would cause it to overheat. <<>> It sounds like the load on the secondary is greater that what the transformer can supply. A transformer is wound for a specific amperage output at a specific voltage. This is stated on the transformer as a VA or in larger transformers as KVA. If you divide the 24 volts into the VA listed on the transformer you will get the maximum amperage value of the transformer. If the device that you are connecting to the transformer is greater in amperage draw that what the transformer can supply, this will cause the heating effect and if left connected eventually burn the transformer out. A fuse should be installed in the secondary 24 volt output, rated at the maximum output of the transformer. This will limit the transformer to its manufacturer's recommended current output.