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William tell shoots an apple off a tree 20.0 meters away and 4.0 meters high The arrow is released from 1.0 meter above ground The arrow travels for 0.500 seconds. What's the velocity of the arrow?
Wiki User
∙ 13y ago
Interesting! Horizontal distance covered by arrow=20m=Vx(t),
put Time=t=0.5s, so Vx=20/.5=40m/s.
Now let us consider vertical motion of the arrow,
Vertical distance=4m-1m=3m. so Use Second equation of motion now.
Y=Vy(t) - gt2/2.
Subtituting the values,
3=Vy(0.5) - 9.8(.5)2/2. Solving for Vy, we get,
Vy= 8.45m/s and Vx=40m/s. now
V2=(Vx2+Vy2) or V2=(8.45)(8.45)+(40)(40)=71.40+1600=1671.40m/s, so
V=(1671.40)1/2=40.88m/s. That is the answer!
Wiki User
∙ 13y ago
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