How precise do you want to get?
Precision method...
Calculate the diagonal of the camera's film image. Compare the lens focal length to that to get your answer.
Example for 35mm camera with 50mm lens:
film image is 24x36; diagonal is square root of (24*24 + 36*36) = 43.267
(remember Pythagorean theorem)? Ratio is 50/43.267 = 1.156. Thus, 50mm lens magnifies image 1.156 times. This is negligible, hence most people consider the 50mm lens to be "normal" for 35mm cameras.
Simple method, same camera & lens:
100 mm lens produces 2x magnification (100/50)
I hope you're not asking because you wish to relate this to telescopes or binoculars. That is a subject I'm not familiar with, and I suspect the field of view for those devices has to be considered. Hope my answer gives you what you needed.
Most consumer cameras are 1/4 x 20 threads. Be careful of the length, too long and it can damage some cameras.
The focal length of a camera's lens refers to the the magnification or telephoto power of the lens and is expressed in the millimeters of the lens, like 100mm, 300mm, etc. www.goldprints.com
To get the exposure level on the sensor correct - it's important in photography on film also. Many cameras attempt to do it automatically.
This describes the focal length range of the lens. It means that the lens can be set between 18mm (a wide angle which takes in a larger field of view) and 200mm (a telephoto, which creates a narrower field of view). ******* Note: the above is certainly true for 35mm format, but focal length is relative to the format. For 4x5 cameras, the equivalent "normal" focal length is around 200mm.
Most cameras don't have a dedicated shutter speed longer than thirty seconds. If you wish to take exposures longer than that, use the bulb function ('B' on most cameras). Bulb allows the shutter to stay open as long as the shutter button is held down. Get a locking cable release, switch camera to bulb, and you can take any length exposure you want.
The focal length of the main optical system and the focal length of the lens forming the image.
I'm not sure I understand your question. If I do, the conversion from focal length of a digital camera to an equivalent 35mm focal length varies based on the cameras sensor size. These sizes vary by camera model. For most Digital SLRs you multiply the camera's focal length by about 1.6, but the multiplier ranges from 1.5 to 2. The multiplier for simple/consumer non-DSLR cameras is somewhere around 4 times.
Because the length of the objectives depends on the total magnification. Example: Magnification: 50x (LPO) You can see that the lower the magnification,the length of objective is the smallest. Magnification: 500x (HPO) You can see that the higher the magnification, the length of objective is bigger than the other objectives. If the objective is lower, the number is lesser -Guinean026
Yes, the magnification based on the length would coincide with the magnification based on the width. However, the object on the slide is only measured by its diameter.
The magnification of a telescope M is the the focal length of the objective Fo over the focal length of the eyepiece Fe so increasing the focal length of the objective increases the magnification. The magnification of a microscope M is approximately tube length L/Fo x 25/Fe. Therefore increasing the focal length of the objective reduces the magnification.
Take the reciprocal of the focal length measured in metres. The optical power of a lens (or mirror) with a focal length on 2.5 metres is 1/2.5 = 0.4 dioptres.
The magnification of the telescope image is(focal length of the objective) divided by (focal length of the eyepiece).The focal length of the objective is fixed.Decreasing the focal length of the eyepiece increases the magnification of the image.(But it also makes the image dimmer.)
The focal length of a telescope is directly related to the magnification in that the longer the focal length, the more magnification you get from the telsceope. How the focal length of a telescope relates to the length of the telescope itself depends on the design of the telescope. In a refracting telescope, the focal length is approximately the length of the telescope. In a reflecting telescope, the focal length is roughly two time the length of the telescope.
The magnification of a telescope is the ratio of the effective focal length of the objective to the focal length of the eyepiece. For example, a small telescope's objective may have a focal length of 800mm. When an eyepiece with a focal length of 25mm is used, the magnification is 800/25 = 32. The term "effective focal length" refers to the focal length of the objective as affected by any "focal extender". Many telescopes are designed to have a short total size, but high power, by "folding" the optical path. A mirror-type objective with a focal length of perhaps 800mm is coupled with a smaller curved mirror that intercepts the last 200mm and extends it to 800mm, a 4x extension, so that the effective focal length of that objective is 3200mm. Use that with a 25mm eyepiece and the magnification is 3200/25 = 128. By the way, if a telescope is smaller than you are, it is seldom much use to view using a magnification greater than 50 to 100. Most objects are best viewed at relatively low powers such as 30 or so.
The magnification of the telescope image is(focal length of the objective) divided by (focal length of the eyepiece).The focal length of the objective is fixed.Decreasing the focal length of the eyepiece increases the magnification of the image.(But it also makes the image dimmer.)
Divide the focal length of the objective lens by the focal length of the eyepiece.
The magnification of a telescope is the ratio of the effective focal length of the objective to the focal length of the eyepiece. For example, a small telescope's objective may have a focal length of 800mm. When an eyepiece with a focal length of 25mm is used, the magnification is 800/25 = 32. The term "effective focal length" refers to the focal length of the objective as affected by any "focal extender". Many telescopes are designed to have a short total size, but high power, by "folding" the optical path. A mirror-type objective with a focal length of perhaps 800mm is coupled with a smaller curved mirror that intercepts the last 200mm and extends it to 800mm, a 4x extension, so that the effective focal length of that objective is 3200mm. Use that with a 25mm eyepiece and the magnification is 3200/25 = 128. By the way, if a telescope is smaller than you are, it is seldom much use to view using a magnification greater than 50 to 100. Most objects are best viewed at relatively low powers such as 30 or so.