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The work done in stretching the spring can be seen as equal to the spring's newfound potential energy, i.e.

V = 1/2*k*(x-x_0)^2 = 1/2*(w^2*m)*(x-x_0_^2) = 1/2*0.70^2*0.05*0.15 = 0.00184 [J]

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Q: With a 50g mass spring undergoes SHM with a frequency of 0.70 Hz how much work is done in stretching the spring 15 cm from its unstretched length and how much energy is then stored in spring?
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